Electric field is proportional to the charge and inversely proportional to the square of distance:

With charge 2q and distance 2r, the electric field is proportional to:
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The new electric field is half of that of the original measured field.
Answer:
800 N
Explanation:
During terminal velocity, air resistance=weight
Yes yes ! How right you are ! Truer words were never spoken.
Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg