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ki77a [65]
3 years ago
10

As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which comp

resses the gases in their blood. What happens to the volume of gas in their blood as the diver rises quickly to the surface?
Physics
1 answer:
faltersainse [42]3 years ago
5 0

Answer:  The volume of gas expands because of the decrease in pressure as he tries to exit the water body, therefore he must take necessary precaution.

Explanation:

Using Boyle's law which states that the  the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature

ie P1VI=P2V2

A diver absorbs compressed nitrogen gas when  he dives into the water body, As he ascends  out of the water body having less pressure, the volume of nitrogen gas which he absorbs will tend to expand following  Boyle's Law.  Therefore a scuba driver should not rises quickly but slowly  to the surface or else the  expanding nitrogen gas can cause tiny bubbles in his blood and tissue to form together with joints pains and eventually  cause decompression sickness needing medical attention.

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In a motor, the combined effect of electric currents and magnetic forces turn electrical energy into which of the following?
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An airplane during departure has a constant acceleration of 3 m / s².
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Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>

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3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>

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24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

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Which term is applied to an object through which light passes?
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Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

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This technique allowed multiple peoples DNA to be compared to look for
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7 0
2 years ago
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
lesya [120]

Answer:

2.73×10¯³⁴ m.

Explanation:

The following data were obtained from the question:

Mass (m) = 0.113 Kg

Velocity (v) = 43 m/s

Wavelength (λ) =?

Next, we shall determine the energy of the ball. This can be obtained as follow:

Mass (m) = 0.113 Kg

Velocity (v) = 43 m/s

Energy (E) =?

E = ½m²

E = ½ × 0.113 × 43²

E = 0.0565 × 1849

E = 104.4685 J

Next, we shall determine the frequency. This can be obtained as follow:

Energy (E) = 104.4685 J

Planck's constant (h) = 6.63×10¯³⁴ Js

Frequency (f) =?

E = hf

104.4685 = 6.63×10¯³⁴ × f

Divide both side by 6.63×10¯³⁴

f = 104.4685 / 6.63×10¯³⁴

f = 15.76×10³⁴ Hz

Finally, we shall determine the wavelength of the ball. This can be obtained as follow:

Velocity (v) = 43 m/s

Frequency (f) = 15.76×10³⁴ Hz

Wavelength (λ) =?

v = λf

43 = λ × 15.76×10³⁴

Divide both side by 15.76×10³⁴

λ = 43 / 15.76×10³⁴

λ = 2.73×10¯³⁴ m

Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.

8 0
3 years ago
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