The given molarity of sodium hydroxide solution = 2.0 M
The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH
Converting 65 mL to L:

Calculating the moles of NaOH in the final solution:

Finding out the volume of 2.0 M solution taken to prepare the final solution:

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.
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Answer:
![[A_t]=54.5\ g](https://tex.z-dn.net/?f=%5BA_t%5D%3D54.5%5C%20g)
Explanation:
Given that:
Half life = 14.0 days
Where, k is rate constant
So,
The rate constant, k = 0.04951 days⁻¹
Initial concentration [A₀] = 60.0 g
Time = 46.7 hrs
Considering, 1 hr = 0.041667 days
So, time = 1.9458 days
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
So,
![[A_t]=54.5\ g](https://tex.z-dn.net/?f=%5BA_t%5D%3D54.5%5C%20g)
Answer:
V₂ = 46.34 mL
Explanation:
Given data:
Initial temperature = 273 K
Initial volume = 50.0 mL
Final temperature = 253 K
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
Charles Law
"The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure"
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
by putting values in formula,
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 50.0 mL × 253 K / 273 k
V₂ = 12650 mL.K / 273 K
V₂ = 46.34mL
Let P be the product solution, A be the 30% alcohol solution and W be the distilled water.
If we multiply the percentage of alcohol to the volume of the stream, we can obtain the amount of alcohol. Alcohol in the product is the sum of the alcohol in the solution and water.
Vp x 0.25 = 50 x 0.3 + Vw x 0
Vp = 60 gallons of product solution
Volume of product = volume of alcohol sol + vol of water
60 = 50 + Vw
Vw = 10 gallons
10 gallons of water must be added.