Answer:-
The reaction of 2-bromopropane reacts with sodium iodide in acetone is an example of Sn2 reaction.
The I - attacks from backside to give the transition state for both.
If we compare the transition state for cyclobromopropane 2-bromopropane then we see in case of cyclobromopropane transition state, one of the H is very close to the incoming I -.
This results in steric strain and less stability of the transition state. Hence 2-bromopropane reacts with sodium iodide in acetone over 104 times faster than bromocyclopropane.
Answer:
Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception
Answer:
My guess is b or c but its robably wrong
Explanation:
I just also need points sorry <3
Your answer is D rods and cones. Hope this helps!! :)
