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Ksivusya [100]
3 years ago
6

I NEED HELP PLEASE, THANKS!

Chemistry
1 answer:
Xelga [282]3 years ago
5 0

Answer:

See explanation

Explanation:

In the scientific method, you always begin with asking a question. Then, you do research, make a hypothesis, and test that hypothesis based on the initial question. If experimental data does not support your hypothesis, then you can restart by asking a new question, based on what you already know. Hope this helps!

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What happens when light passes through a solution? perform an activity with a homogenous to expalin what happen when light pass
Brilliant_brown [7]

Answer:

light bends and makes effects in the water

Explanation:

6 0
2 years ago
The ph3 molecule is polar. does this offer experimental proof that the molecule cannot be planar? explain.
Alex
<span>Answer: if it was planar the center of the negative forces and the center of the positive forces would be at the same place, meaning no di-poles would form so it wouldnt be polar. as it is polar it therefore cannot be planar. the neagative center(pole) is above the the positive one due to the pair of unbonded electrons.</span>
7 0
3 years ago
Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
3 years ago
A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita
mestny [16]

Answer:

The answer is:

(a) NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b) NaCl

(c) 0.211 g

Explanation:

Given:

The mass of NaCl,

= 0.0860 g

The molar mass of NaCl,

= 58.44 g/mol

The volume of AgNO_3,

= 30.0 ml

or,

= 0.030 L

Molarity of AgNO_3,

= 0.050 M

Moles of NaCl will be:

= \frac{Given \ mass}{Molar \ mass}

= \frac{0.0860}{58.44}

= 0.00147 \ mol

now,

Moles of AgNO_3 will be:

= Molarity\times Volume

= 0.050\times 0.030

=0.0015 \ mol

(a)

The reaction is:

⇒ NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b)

1 mole of NaCl react with,

= 1 mol of AgNO_3

0.0015 mol AgNO_3 needs,

= 0.00150 \ mol \ NaCl

Available mol of NaCl < needed amount of NaCl

So,

The limiting reagent is "NaCl".

(c)

The precipitate formed,

= 0.00147\times \frac{1}{1}\times \frac{143.32}{1}

= 0.211 \ g \ AgCl

4 0
3 years ago
What is the mass of 8.90 moles of magnesium chloride, MgCl2?
Korolek [52]
No of moles of MgCl2 = weight of MgCl2 / Molecular weight of MgCl2 Weight of MgCl2 =moles of MgCl2 x molecular mass of MgCl2 = 8.90 x 95=845.5 gm
6 0
3 years ago
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