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3 years ago

9 tenths plus two fifths

Physics

2 answers:

Rasek [7]3 years ago

7 0

13/10 or 1 3/10 Hope this helps!!!!

inysia [295]3 years ago

4 0

4/10+9/10=13/10 also known as 1 3/10

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A lead ball is dropped into a lake from a diving board 5m above the water . It hits the water with a certain velocity and then s

pickupchik [31]

1. Depth of the lake: 50 m

Explanation:

The first part of the problem can be solved by using conservation of energy.

When it is dropped, all the mechanical energy of the ball is potential energy, given by:

$U=mgh$

where m is the mass, g is the gravitational acceleration and h is the height.

When the bal hits the water, all the mechanical energy has been converted into kinetic energy:

$K=\frac{1}{2}mv^2$

where m is the mass and v is the speed. Equalizing the two terms, we have:

$mgh=\frac{1}{2}mv^2\\2gh=v^2\\v=\sqrt{2gh}=\sqrt{2(10 m/s^2)(5 m)}=10 m/s$

Then the ball travels in the water, keeping this constant velocity, for t=5 s. So, the total distance traveled underwater (which is the depth of the lake) is

$d=vt=(10 m/s)(5 s)=50 m$

2. Average velocity: 9.2 m/s

Explanation:

The average velocity during the whole path of the ball is equal to the ratio between the total distance traveled and the total time taken:

$v=\frac{d}{t}$

We already know the total distance: 5 meters above the water and 50 m underwater, so

d = 5 m + 50 m = 55 m

For the total time, we need to calculate the time spent above the water, which is given by

$S=\frac{1}{2}gt_a^2\\t_a = \sqrt{\frac{2S}{g}}=\sqrt{\frac{2(5 m)}{10 m/s^2}}=1 s$

So the total time is: 1 second above the water + 5 seconds underwater:

t = 1 s + 5 s = 6 s

Therefore, the average velocity is

$v=\frac{55 m}{6 s}=9.2 m/s$

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2 years ago

Billy and Caleb are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spil

Ipatiy [6.2K]

Answer:

Increased regulation and better shipping containers

Explanation:

Plz mark brainliest

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2 years ago

Read 2 more answers

Three positive charges A, B, and C, and a negative charge D are placed in a line as shown in the diagram. All four charges are o

polet [3.4K]

Answer:

a. charge C experiences the greatest net force, and charge B receives the smallest net force

b. ratio=9

Explanation:

<u>Electrostatic Force</u>

Two point-charges $q_1$ and $q_2$ separated a distance d will exert a force on each other of a magnitude given by the Coulomb's formula

$\displaystyle F=\frac{k\ q_1\ q_2}{r^2}$

Where k is the proportional constant of value

$k=9*10^9\ N.m^2/c^2$

The diagram provided in the question shows four identical charges (let's assume their value is Q) separated by identical distance (of value d). The force between the charges next to others is

$\displaystyle F_1=\frac{k\ Q\ Q}{d^2}$