Question

Initially, the translational rms speed of a molecule of an ideal gas is 349 m/s. The pressure and volume of this gas are kept constant, while the number of molecules is increased by a factor of 4. What is the final translational rms speed of the molecules

Answer 1

Answer:

The final translational rms speed is 247.51 m/s

Explanation:

The translational rms speed, v= 349 m/s.

Translational rms speed of a molecule of an ideal gas is:

• v=$\sqrt{\frac{3KT}{M} }$

If we keep the pressure and volume of the gas constant,

P1=P2=P and V1=V2=V

while the number of molecules is increased by a factor of 4,

n2=4n1

for constant P, V and R

n1RT1=n2RT2

T2=T1/2

so, final translational rms speed, v2:

• v2=$\sqrt{\frac{3kT2}{M}}$

v2=$\frac{v1}{\sqrt{2} }$

substituting values,

v2=349/ sqrt(2)

final translational rms speed:

v2=247.51 m/s

learn more about translation rms speed here:

brainly.com/question/13778652

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