When a photon hits an electron <span>the photon will be partially </span>absorbed<span>and the electron emits another photon with lower energy.</span>
Given, a = -3.2m/s²
v = 5m/s
t = 10s
u = ?
Using kinematic equation,
v = u + at
5 = u -3.2* 10
5 = u - 32
u = 32 + 5
u = 37 m/s
At boiling point :
H = mL
Where m = mass, L =specific latent heat
So from the formula for boiling, you need to know the mass and specific latent heat of vaporization
C. is the best answer.
Answer:
(3) mass-energy must be conserved
Explanation:
As we know that gamma rays are mass less and charge less photons which will have sufficient energy.
Now in case of Pair production the gamma photons convert its whole energy into mass by the law of Einstein's mass energy equivalence relation.
As per his relation we can say
here we will have
[tex]\Delta m[\tex] = mass produced
now we also have to think that here the two particles must have a pair of particles and antiparticles so that the combined mass system will have energy equivalent to the energy of gamma photons and also it must follow the conservation of charge
So here it will form an electron and a positron such that total charge will be zero and the energy will be same as energy of gamma photon.
Explanation:
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