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Harlamova29_29 [7]
3 years ago
12

Please help me on this question, it would mean a lot! Thank you! Only question one, thank you

Physics
1 answer:
Akimi4 [234]3 years ago
3 0
The answer to your question is SPEED.
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An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0 with the horizontal. The coeffici
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Answer:

V = 10.88 m/s

Explanation:

V_i =initial velocity = 0m/s

a= acceleration= gsinθ-\mu_kcosθ

putting values we get

a= 9.8sin25-0.2cos25= 2.4 m/s^2

v_f= final velocity and d= displacement along the inclined plane = 10.4 m

using the equation

v^2_f=v^2_i-2as

v^2_f=0^2-2(2.4)(10.4)

v_f= 7.04 m/s

let the speed just before she lands be "V"

using conservation of energy

KE + PE at the edge of cliff = KE at bottom of cliff

(0.5) m V_f^2 + mgh = (0.5) m V^2

V^2 = V_f^2 + 2gh

V^2 = 7.04^2 + 2 x 9.8 x 3.5

V = 10.88 m/s

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If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time.
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Answer:

F=mkv

Explanation:

Given that

v = v_i - kx

We know that acceleration a given as

a=\dfrac{dv}{dt}

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