The acceleration that Andrew experience during his ride is 3.6m/s²
The formula for calculating centripetal acceleration is expressed as:
a = v²/r
v is the speed
r is the radius
Given the following expression
v = 6m/s
r = 10m
Substitute the given parameters into the formula
a = 6²/10
a = 36/10
a = 3.6m/s²
Hence the acceleration that Andrew experience during his ride is 3.6m/s²
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Answer:
A los 10 segundos su velocidad será 15 
Explanation:
La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.
En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:
- Una aceleración grande significa que la velocidad cambia rápidamente.
- Una aceleración pequeña significa que la velocidad cambia lentamente.
- Una aceleración cero significa que la velocidad no cambia.
La aceleración "a" puede ser calculada mediante la expresión:

En este caso:
- a= 1

- vfinal= ?
- vinicial= 5

- tiempo= 10 s
Reemplazando:

Resolviendo se obtiene:
1
*10 s= vfinal - 5 
10
= vfinal - 5 
10
+ 5
= vfinal
15
= vfinal
<u><em>A los 10 segundos su velocidad será 15 </em></u>
<u><em></em></u>
Answer:
(a) 2.33 A
(b) 15.075 V
Explanation:
From the question,
The total resistance (Rt) = R1+R2 = 3.85+6.47
R(t) = 10.32 ohms.
Applying ohm's law,
V = IR(t)..........equation 1
Where V = Emf of the battery, I = current flowing through the circuit, R(t) = combined resistance of both resistors.
Note: Since both resistors are connected in series, the current flowing through them is the same.
Therefore,
I = V/R(t)............. Equation 2
Given: V = 24 V, R(t) = 10.32 ohms
Substitute these values into equation 2
I = 24/10.32
I = 2.33 A.
Hence the current through R1 = 2.33 A.
V2 = IR2.............. Equation 3
V2 = 2.33(6.47)
V2 = 15.075 V
Your question kind of petered out there towards the end and you didn't specify
the terms, so I'll pick my own.
The "Hubble Constant" hasn't yet been pinned down precisely, so let's pick a
round number that's in the neighborhood of the last 20 years of measurements:
<em>70 km per second per megaparsec</em>.
We'll also need to know that 1 parsec = about 3.262 light years.
So the speed of your receding galaxy is
(Distance in LY) x (1 megaparsec / 3,262,000 LY) x (70 km/sec-mpsc) =
(150 million) x (1 / 3,262,000) x (70 km/sec) =
<em>3,219 km/sec </em>in the direction away from us (rounded)
Organic materials continue to be the largest component of MSW. Paper and paperboard account for 27 percent and yard trimmings and food account for another 28 percent. Plastics comprise about 13 percent; metals make up 9 percent; and rubber, leather, and textiles account for 9 percent.