Answer:
The answer to your question is a = 1.3 m/s²
Explanation:
Centripetal acceleration is the motion of a body that transverse a circular path.
Data
mass = 7 kg
radius = r = 1.3 m
angular rate = w = 1.0 rev/s
centripetal acceleration = a = ?
Formula
a = rw²
Substitution
a = (1.3)(1)²
Simplification and result
a = 1.3 m/s²
Answer:
f=1/t is the equation of frqency
That depends on what type of pressure you are attempting to measure, to measure Atmospheric pressure, you would use a Barometer. To measure things like tires, you could use a Tire Pressure Gauge. For Industrial processes and boilers, you would use a Manometer. For pressure vessels, you would use a Bordon Gauge. <span />
Answer:
Explanation:
First of all, well calculate the spring constant k
K = 2Ei/x^2
Where Ei = initial work required
x = initial stretch length
k = 2×7/0.017^2 = 48443J/m^2
Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m
EF = kx^2/2
48443 × 0.053^2/2 = 68J
Work done in stretching additional 3.6cm is equal to
68J-7J = 61J
The fact that the woman falls at a constant velocity means its acceleration is zero.
For Newton's second law, the resultant of the forces acting on a body is equal to the product between the mass m of the body and its acceleration a:

In our problem, the acceleration is zero, so the resultant of the forces should be zero as well.
Only two forces are acting on the woman: the air resistance R (upward, 500 N) and the weight W (downward). The resultant of these two forces is zero, so


and since the air resistance R is 500 N, then the weight (the gravitational force) of the woman is 500 N as well.