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maks197457 [2]
3 years ago
14

Newton's 3rd Law is based on what type of forces?

Physics
2 answers:
kupik [55]3 years ago
8 0

Explanation:

According to Newton's third law of motion, whenever two objects interact, they exert equal and opposite forces on each other. This is often worded as 'every action has an equal and opposite reaction'.

NikAS [45]3 years ago
3 0

Answer: His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

Explanation:

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Which of the following scenarios will cause the current to stop flowing within a current​
ella [17]

Answer:

The switch within the closed circuit is opened and it stops the flow of current in a circuit.

Explanation:

  • Current is defined as a flow of electrons in a system or a circuit.
  • There are two basic things needed for current to flow in a system
  • One is the electro-motive force and the other is the complete path for current to flow.
  • If a switch in a closed circuit gets opened, it restricts the path of current flow.
  • Thus it stops the current to be flowed through the circuit.
7 0
3 years ago
The term “distance” refers to ?
Mnenie [13.5K]

Answer:

numerical measurement of how far apart objects or points are.

Explanation:

3 0
4 years ago
What would be different about the heat of fusion & vaporization ? and why?​
exis [7]

fusion is when solid changes it's state to liquid

and vaporization is when liquid changes it's state to gas

so the difference between fusion and vaporization is the state

3 0
3 years ago
Aluminum Rod#1 has a length L and a diameter d. Aluminum Rod#2 has a length 2L and a diameter 2d. If Rod#1 is under tension T an
Virty [35]

Answer:D

Explanation:

For Rod 1

length,diameter and Tension is L, d and T

for Rod 2 length,diameter and Tension is 2L, 2d and 2T

Change in Length is given by

\Delta =\frac{PL}{AE}

where P=load

L=length

A=area of cross-section

E=young's Modulus

\Delta _1=\frac{TL}{\frac{\pi d^2}{4}E}

since both are aluminium rod therefore E is common

\Delta _2=\frac{2T\cdot 2L}{\frac{\pi (2d)^2}{4}E}

\Delta _2=\frac{TL}{\frac{\pi d^2}{4}E}=\Delta _1

Thus extension in both the rods are same

3 0
3 years ago
Help pls I have to do an exam, thx in advance
iogann1982 [59]
Should be A, i am not absolutely certain but all the other options just sound ridiculous
3 0
3 years ago
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