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3 years ago

To gain an idea as to how many atoms are in a gram or so of copper, use the larger balance

Chemistry

1 answer:

anygoal [31]3 years ago

7 0

Answer:

Explanation:

To solve this problem, we must understand the relationship between mass of a substance and the number of atoms.

Atoms are the smallest indivisible particles of any matter. A substance can be made up of several number of atoms in their space.

The mass of any substance is a function of the amount of atoms its contains.

The mass of a substance is related in chemistry to the amount of atoms its contains using the parameter called the number of moles.

A mole is the amount of substance that contains the Avogadro's number of particles. This number is 6.02 x 10²³ particles. The particles here can be protons, neutrons, electrons, atoms e.t.c.

Now,

Number of moles = $\frac{mass}{molar mass}$

Molar mass of copper = 63.6g/mole

Number of moles = $\frac{2}{63.6}$ = 0.03mole

Since 1 mole of a substance contains 6.02 x 10²³atoms

0.03 mole of copper will contain 0.03 x 6.02 x 10²³atoms

= 1.89 x 10²² atoms

He needs to add 1.89 x 10²² atoms to make 2g of the sample.

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Which represents the empirical formula for a3B9

Viktor [21]

A3B9 represents a molecular formula. The representation of the empirical formula for this compound is AB3. This is so because the empirical formula is the simplest ratio of the atoms present in the molecule. You get AB3 when you divide the subscripts of A3B9, this is 3 and 9, by the greatest common factor, which is 3. 3/3 = 1 and 9/3 = 3, so the subscripts for the empirical formula are 1 and 3, which is what AB3 represents. <span>Answer: AB3.</span>

3 0

3 years ago

A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. T

Norma-Jean [14]

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${96.0\ kPa}\times {10.0\ L}={P_2}\times {45.0\ L}$

${P_2}=\frac {{96.0}\times {10.0}}{45.0}\ kPa$

${P_2}=21.3\ kPa$

The final pressure of the gas is:- 21.3 kPa

3 0

3 years ago

Calculate the density of CO2 in g/cm3 at room temperature(25 degrees Celsuis) and pressure(1 atm) assuming it acts as an ideal g

Readme [11.4K]

Answer:

$density=1.8x10^{-3}g/mL$

Explanation:

Hello,

Considering the ideal equation of state:

$PV=nRT$

The moles are defined in terms of mass as follows:

$n=\frac{m}{M}$

Whereas $M$ the gas' molar mass, thus:

$PV=\frac{mRT}{M}$

Now, since the density is defined as the quotient between the mass and the volume, we get:

$P=\frac{m}{V} \frac{RT}{M}$

Solving for $m/V$ :

$density= m/V=\frac{PM}{RT}$

Thus, the result is given by:

$density=\frac{(1atm)(44g/mol)}{[0.082atm*L/(mol*K)]*298.15K} \\density=1.8g/L=1.8x10^{-3}g/mL$

Best regards.

8 0

3 years ago

Heat Transfer Lab

scoray [572]

Heat Transfer Lab

The following represents a lab set up for heat transfer. The cup on the left started with boiling water at 100 degrees C and the cup on the right has water at 20 degrees C. There is an aluminum bar between the two cups allowing heat to transfer from one cup into the other. The set up will be left alone for 20 minutes and temperatures of each cup of water will be recorded every minute for 20 minutes.

mag-aral ka

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3 years ago

In ____________ reactions, certain molecules are broken down; in the process they release energy which is captured when high-ene

Rudik [331]

Answer:

Exergonic ,Endergonic,low concentration area,high

Explanation:

In exergonic reaction,certain molecules are broken down;in the process they release energy which is captured when high energy molecules(such as ATP and NADH) are formed.

The breakdown of these molecules can be coupled to thermodynamically unfavorable processes such as Endergonic reactions or pumping og hydrogen ion from low concentration areas to high concentration areas.

3 0

3 years ago