In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
rbon group Secondary carbon (2o) = carbon bonded to 2 other carbon groups Tertiary carbon (3o) = carbon bonded to 3 other carbon groups Quaternary carbon (4o) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
1 answer:
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
You might be interested in
Answer : The volume of gas will be 29.6 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 12 atm
= final pressure of gas = 14 atm
= initial volume of gas = 23 L
= final volume of gas = ?
= initial temperature of gas = 200K
= final temperature of gas = 300K
Now put all the given values in the above equation, we get the final pressure of gas.
Therefore, the new volume of gas will be 29.6 L
Rate equation for first order reaction is as follows:
Here, k is rate constant of the reaction, t is time of the reaction, is initial concentration and
is concentration at time t.
The rate constant of the reaction is .
(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,
Thus, time required to destroy 90% of the chemical is 23.03 days.
(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,
Thus, time required to destroy 99% of the chemical is 46.06 days.
(c) Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,
Thus, time required to destroy 99.9% of the chemical is 69.09 days.