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4 years ago

Two students made the Lewis dot diagrams of H2O. The diagrams are as shown.

Chemistry

2 answers:

lawyer [7]4 years ago

8 0

Answer:

only student a

Explanation:

netineya [11]4 years ago

7 0

Answer:

Only student A

Explanation:

don’t worry I got a 100

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How many moles of magnesium are in 3. 01 x 10^22 atoms of magnesium.

marshall27 [118]

Answer:

Explanation:

1 mol of anything is 6.02 * 10^23 atoms (in this case)

x mol of 3.01 * 10^22

Set up the proportion

1/x = 6.02*10^23 / 3.01 * 10^22 Cross multiply

x*6.02 * 10^23 = 1 * 3.01 * 10^22 Divide by 6.02*10^23

x = 3.01 * 10^22 / 6.02*10^23

x = 1/(2 * 10)

x = 1/20 mol

x = 0.05 mol

5 0

3 years ago

Which of the following fractions can be used in the conversion of 25 m3 to the unit cm3?

zaharov [31]

your answer would be C hope this helps

8 0

4 years ago

What did the scientists have to consider before releasing the dragonflies into the wild? Why?

pentagon [3]

Maybe they had to consider the habitat to make sure the habitat they were releasing the dragonflies into would be appropriate for the dragonflies.

3 0

3 years ago

Read 2 more answers

Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation f

dmitriy555 [2]

Answer: The mass of cryolite produced is 51.48 kg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For aluminium oxide:

Given mass of aluminium oxide = 12.5 kg = 12500 g (Conversion factor: 1 kg = 1000 g)

Molar mass of aluminium oxide = 101.96 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium oxide}=\frac{12500g}{101.96g/mol}=122.6mol$

For NaOH:

Given mass of NaOH = 55.4 kg = 55400 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{55400g}{40g/mol}=1389mol$

For HF:

Given mass of HF = 55.4 kg = 55400 g

Molar mass of HF = 20 g/mol

Putting values in equation 1, we get:

$\text{Moles of HF}=\frac{55400g}{20g/mol}=2770mol$

For the given chemical reaction:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)$

By Stoichiometry of the reaction:

1 mole of aluminium oxide reacts with 6 moles of sodium hydroxide and 12 moles of HF.

So, 122.6 moles of aluminium oxide will react with $(6\times 122.6)=735.6mol$ of sodium hydroxide and $(12\times 122.6)=1471.2mol$ of HF

As, given amount of NaOH and HF is more than the required amount. So, they are considered as an excess reagent.

Thus, aluminium oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 122.6 moles of aluminium oxide will produce = $\frac{2}{1}\times 122.6=245.2mol$ of cryolite

Now, calculating the mass of cryolite by using equation 1:

Molar mass of cryolite = 209.94 g/mol

Moles of cryolite = 245.2 mol

Putting values in equation 1, we get:

$245.2mol=\frac{\text{Mass of cryolite}}{209.94g/mol}\\\\\text{Mass of cryolite}=(245.2mol\times 209.94g/mol)=51477.3g$

Converting this into kilograms, we use the conversion factor:

1 kg = 1000 g

So, $51477.3 g\times (\frac{1kg}{1000g})=51.48kg$

Hence, the mass of cryolite produced is 51.48 kg

7 0

3 years ago

H. Nitrogen gas and hydrogen gas combine to produce ammonia gas (NH3).

DedPeter [7]

Answer:

27.3 L

Explanation:

Reaction

N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g)
This is the basic reaction at STP

Solving

10 g N₂ x 1 mol NH₃/28 g N₂ x 3 mol H₂/1 mole N₂
⇒ 1.07 mol H₂

V = nRT/P [From Ideal Gas Equation]
V = 1.07 x 62.36 x 298 K / 735
V = 27.3 L

4 0

2 years ago