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4 years ago

Two students made the Lewis dot diagrams of H2O. The diagrams are as shown.

Chemistry

2 answers:

lawyer [7]4 years ago

8 0

Answer:

only student a

Explanation:

netineya [11]4 years ago

7 0

Answer:

Only student A

Explanation:

don’t worry I got a 100

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What is the density of CO gas if 0.196 occupies a volume of 100 no

shusha [124]

The density of CO gas if 0.196g occupies a volume of 100mL is0.00196gmL or 0.00196 grams per milliliter

3 0

3 years ago

A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the

Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

$\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%$

Thus, we solve for the molar mass of the metal to obtain:

$59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol$

For the subsequent problems, we proceed as follows:

$4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2$

$0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH$

$0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH$

Regards!

7 0

3 years ago

A common laboratory reaction is the neutralization of an acid with a base. When 31.8 mL of 0.500 M HCl at 25.0°C is added to 68.

lord [1]

Answer:

The correct answer to the following question will be "90.6 kJ/mol".

Explanation:

The total reactant solution will be:

$(31.8 \ mL+68.9 \ mL)\times 1.07\ g/mL = 107.74 \ g$

The produced energy will be:

$=4.18 \ J/(gK)\times 107.74 \ g\times (28.2-25.0)K$

$=450.35\times 3.2$

$=1441.12 \ J$

The reaction will be:

⇒ $HCl+NaOH \rightarrow NaCl+H_{2}O$

Going to look at just the amounts of reactions with the same concentrations, we notice that they're really comparable.

Therefore, the moles generated by NaCl will indeed be:

= $(\frac{31.8}{1000} \ L)\times (0.500 \ M \ HCl/L)\times \frac{1 \ mol \ NaCl}{1 \ mol \ HCl}$

= $0.0318\times 0.500$

= $0.0159 \ mole \ of \ NaCl$

Now,

= $\frac{1441.12 \ J}{0.0159 \ moles \ NaCl}$

= $906364.7$

= $90.6 \ KJ/mol \ NaCl$

7 0

3 years ago

What is the percent by mass of potassium in K3Fe(CN)6?

yawa3891 [41]

The percent by mass of potassium in K3Fe(CN)6 is 35.62%.

3 0

4 years ago

Read 2 more answers

Heat of fusion (?Hfus) is used for calculations involving a phase change between solid and liquid, with no temperature change. F

Butoxors [25]

Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)

Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

q = 38,5 kJ

I hope it helps!

6 0

3 years ago