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Fed [463]
3 years ago
11

How to separate sand from salt

Chemistry
1 answer:
IRINA_888 [86]3 years ago
6 0
Put the salt and sand in some water.
the salt will not be visible but the sand will
now strain the the sand from the water
now boil the water and now the water will boil away and now you will just have salt left.
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Which of the following statements regarding glucose is FALSE?a) Glucose is the main component of starch and glycogen.b) Glucose
marishachu [46]

Answer:

The correct option is C.

Explanation:

Carbohydrates are one of the macro molecules that are consumed by living organisms. The end product of carbohydrate is glucose. Glucose is a very important fuel that the body cells used to produce energy, which they use to carry out their daily activities. Glucose is also known as blood sugar and it is the only fuel that living cells can use for the production of ATP. Other food macro molecules such as lipids and proteins can also be converted to glucose if there is a need for that. Glucose is always stored in the body in form of glycogen.

The statement given in option C about glucose is wrong because glucose is a monosaccharide and not a disaccharide.

8 0
3 years ago
If the Dry bulb reads 25 degrees Celsius and the wet bulb reads 22
Nitella [24]

Answer:

Relative humidity is low .

Explanation:

The wet bulb reads low temperature because due to low humidity of atmosphere , evaporation of water takes place from the wet bulb which makes the bulb cool and therefore it reads lower temperature . In the process of evaporation , heat equal to latent heat of vaporization is taken from the bulb and it loses temperature.

6 0
2 years ago
At stp what is the volume of 5.35 moles of methane ch4​
Nookie1986 [14]

Answer:

22.4 L

Explanation:

8 0
2 years ago
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
2 years ago
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Which formula represents an ionic compound?
kumpel [21]
When 2 elements are combined it creates an ionic compound
7 0
3 years ago
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