Answer:
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Answer:
Ionic compounds have a metal and nonmetal.
Ionic compounds are made up of ions.
Explanation:
You did not provide any formulas for me to correct, but:
- ionic compounds tend to have metals and nonmetals. (EX: NaCl)You can look at the periodic table to see which elements are metals and which are not.
- ionic compounds are made up of ions. Ions are elements that have a charge (Like
or
). To have a correct ionic compound, make sure that the ions inside of it "cancel" each other out.
EX: Na has a +1 charge. Cl has a -1 charge. When they are paired up, they successfully cancel each other out (become neutral) and become the ionic compound NaCl.
The chart below shows you the charge of each element. Make sure the charge of the elements in an ionic compound "cancel" each other out.
The very last chart shows the metals and nonmetals
Chart 1:found in https://chem.libretexts.org/Courses/Oregon_Tech_PortlandMetro_Campus/OT_-_PDX_-_Metro%3A_General_Chemistry_I/03%3A_Nuclei_Ions_and_the_Periodic_Table/3.03%3A_Predicting_Charges_of_Ions
Chart 2: found in https://sciencenotes.org/metals-metalloids-nonmetals/
<u>Answer:</u> The pH value of the solution is 10 and the solution is basic in nature.
<u>Explanation:</u>
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
![[OH^-]=1\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

There are three types of solution: acidic, basic and neutral
To determine the type of solution, we look at the pH values.
- The pH range of acidic solution is 0 to 6.9
- The pH range of basic solution is 7.1 to 14
- The pH of neutral solution is 7.
As, the pH of the solution is 10 and is lying in the range of basic solution, so the solution is basic in nature.
We first calculate the energy contained in one photon of this light using Planck's equation:
E = hc/λ
E = 6.63 x 10⁻³⁴ x 3 x 10⁸ / 590 x 10⁻⁹
E = 3.37 x 10⁻²² kJ/photon
Now, one mole of atoms will excite one mole of photons. This means that 6.02 x 10²³ photons will be excited
(3.37 x 10⁻²² kJ/photon) x (6.02 x 10²³ photons / mol)
The energy released will be 202.87 kJ/mol
A molecule is usually reserved to represent the smallest particle of a compound.