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ivann1987 [24]
3 years ago
14

5. You are investigating an arson scene and you find a corpse in the rubble, but you suspect that the victim did not die as a re

sult of the fire. Instead, you suspect that the victim was murdered earlier, and that the blaze was started to cover up the murder. How would you go about determining whether the victim died before the fire
Chemistry
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:

See the answer below.

Explanation:

Fire has three major components:

  • Heat
  • Smoke
  • Gases ( in form of CO, CO2 etc)

If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.

If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.

<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>

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swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at T_1  = K_1

K_2 = rate constant at T_2 = 3K_1

Ea = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 293 K

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Now put all the given values in this formula, we get:

\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]

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3 years ago
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I think that the answer you are looking for is B.

Hope it helps :)

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In the equation 2 H2 + O2 → 2 H2O, the H2 molecules are ________ and the H2O molecules are ________.
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