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neonofarm [45]
3 years ago
15

Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.

Chemistry
2 answers:
Phantasy [73]3 years ago
7 0

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Sodium carbonate is an ionic compound and its dissociation will lead to the formation of its respective ions.

This compound is formed by the combination of sodium and carbonate ions.

The chemical equation for the dissociation of sodium carbonate follows:

Na_2CO_3(aq.)\rightarrow 2Na^+(aq.)+CO_3^{2-}(aq.)

By Stoichiometry of the reaction:

1 mole of sodium carbonate produces 2 moles of sodium ions and 1 mole of carbonate ion.

Hence, the chemical equation is written above.

Savatey [412]3 years ago
6 0
Net overall dissociation:
Na2CO3 ---> 2Na(-) + CO3(2-)

*The ion charge is in parenthesis
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Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
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Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

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HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

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Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

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From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

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Now we have to calculate the volume of CO_2 by using ideal gas equation.

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Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

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