Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.
2 answers:
<u>Answer:</u> The chemical equation is written below.
<u>Explanation:</u>
Sodium carbonate is an ionic compound and its dissociation will lead to the formation of its respective ions.
This compound is formed by the combination of sodium and carbonate ions.
The chemical equation for the dissociation of sodium carbonate follows:
By Stoichiometry of the reaction:
1 mole of sodium carbonate produces 2 moles of sodium ions and 1 mole of carbonate ion.
Hence, the chemical equation is written above.
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<h3>Answer:</h3>
= 5.79 × 10^19 molecules
<h3>Explanation:</h3>The molar mass of the compound is 312 g/mol
Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)
We are required to calculate the number of molecules present
We will use the following steps;
<h3>Step 1: Calculate the number of moles of the compound </h3>Therefore;
Moles of the compound will be;
= 9.615 × 10⁻5 mole
<h3>Step 2: Calculate the number of molecules present </h3>Using the Avogadro's constant, 6.022 × 10^23
1 mole of a compound contains 6.022 × 10^23 molecules
Therefore;
9.615 × 10⁻5 moles of the compound will have ;
= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules
= 5.79 × 10^19 molecules
Therefore the compound contains 5.79 × 10^19 molecules