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ikadub [295]
3 years ago
9

Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
 However, there is no variable x in the function.
 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
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Use the order of operations to simplify the given expression.<br> 4−6+2⋅7
andrezito [222]

Answer:

19

Step-by-step explanation:

PEMDAS

no parenthesis

no exponents

4-6+2 x 7

4-6+ 17

no division

4-6=2

2+17

19 is the answer

6 0
4 years ago
Read 2 more answers
Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999
sp2606 [1]

Answer:

1 999 000

Step-by-step explanation:

Formula:

1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right)  }{2}

………………………………………

Then

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{3998000  }{2}

1+2+3+....+1997+1998+1999=1999000

7 0
2 years ago
The Maine Public Health Department reported that there have been 90 flu cases requiring hospitalization in Portland, ME (populat
Zigmanuir [339]

Answer:

The prevalence rate of flu cases requiring hospitalization thus far in 2018 is:

= 0.13%

Step-by-step explanation:

a) Data and Calculations:

Population of Portland, ME = 70,000

Number of flu cases requiring hospitalization on February 1st, 2018 = 43

Number of flu cases requiring hospitalization on July 4th, 2018 = 90

The prevalence rate of flu cases requiring hospitalization thus far in 2018 = 90/70,000 * 100 = 0.13%

b) The prevalence rate represents the proportion of the population of Portland, ME, who have the flu at the time that the Maine Public Health Department reported the number of flu cases requiring hospitalization on July 4th, 2018.

3 0
3 years ago
Help answering this question please
abruzzese [7]
Answer: ok
explanation:
5 0
3 years ago
How much would $200 invested at 4% interest compounded annually be worth after 8 years?
Maru [420]
You can work this out by doing the sum 200×1.04^8.
This gives the answer 273.71381
So it will be worth $273.71
4 0
3 years ago
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