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ikadub [295]
3 years ago
9

Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
 However, there is no variable x in the function.
 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
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Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

\frac{sin(B)}{b} = \frac{sin(C)}{c}

\frac{sin(B)}{24} = \frac{sin(82)}{29}

sin(B)*29 = sin(82)*24

\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}

sin(B) = \frac{sin(82)*24}{29}

sin(B) = 0.8195

B = sin^{-1}(0.8195)

B = 55.0

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

\frac{a}{sin(43)43} = \frac{24}{sin(55)}

Cross multiply

a*sin(55) = 25*sin(43)

a = \frac{25*sin(43)}{sin(53)}

a = 20 (approximated)

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