All categories

3 years ago

Write an expression that shows how to multiply 7 * 256 using expanded form and the distributive property

Mathematics

1 answer:

maxonik [38]3 years ago

4 0

7x6+7x50+7x200=answer

You might be interested in

Help ASAP

Vlada [557]

Answer:

I hope this helps you!

H = 1,4

8 0

1 year ago

The water inside a right cylinder tank is 6 inches above the bottom part of the tank of radius 1 feet and length 2 feet. Find th

ASHA 777 [7]

Answer:

Step-by-step explanation:

Volume of the water is equivalent to the volume of a cylinder = πr²h where;

r is the radius of the cylindrical tank

h is the height of the water

Given parameters

radius of the cylindrical tank r = 1feet = 12 inches

height of the water inside the tank = 6inches

Volume of the water = πr²h

Volume of the water = π(12)²*6

Volume of the water = π*144*6

Volume of the water = 864π in³

Hence the volume of the water is 864π in³

8 0

2 years ago

Read 2 more answers

The median price, P, of a home rose from 80$ thousand in 1980 to 240$ thousand in 2000. Let t be the number of years since 1980.

Elena L [17]

Answer:

Step-by-step explanation:

8 0

2 years ago

Profit is the difference between revenue and cost. The revenue, in dollars, of a company that manufactures televisions, can be m

Irina-Kira [14]

Answer:

50,700

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x

Fiesta28 [93]

Given function is

$f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.$

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

$kx^2-5$

so RHD= $k(-4)^2-5$

Now set both equal

$k(-4)^2-5=3(-4)+k$

$16k-5=-12+k$

$16k-k=-12+5$

$15k=-7$

$k=-\frac{7}{15}$

k=-0.47

Hence final answer is -0.47.

7 0

2 years ago