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Marta_Voda [28]
3 years ago
10

What would be the kinetic energy of an arrow having a potential energy of 50 J after it is shot from a bow?

Physics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

The kinetic energy of the arrow is equaled to the potential energy of the stretching of the bow, which in this case is 50 J.

Explanation:

Potential energy converts to kinetic as soon as it begins to move.

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A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Complete the following statemen
Eva8 [605]

Answer:

Keeping the speed fixed and decreasing the radius by a factor of 4

Explanation:

A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :

a=\dfrac{v^2}{R}

We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"

It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,

R' = R/4

New centripetal acceleration will be,

a'=\dfrac{v^2}{R'}

a'=\dfrac{v^2}{R/4}

a'=4\times \dfrac{v^2}{R}

a'=4\times a

So, the centripetal acceleration of the ball can be increased by a factor of 4.

7 0
3 years ago
Using this information...
Pepsi [2]

19.2\:\text{m/s}

Explanation:

At the top of the tree, the velocity of the pebble is purely horizontal so we can calculate it as

v_{y} = v_{0y} = v_0\cos 40° = (25\:\text{m/s})(0.766)

\:\:\:\:\:= 19.2\:\text{m/s}

6 0
3 years ago
A train is moving with a velocity of 70 km/h. If north is taken as the positive direction, what is the direction of movement of
Anna11 [10]

Answer:

+70 km/h north

Explanation:

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3 years ago
Explain: What happens to the velocity of a stream as the size of the sediment increases?
artcher [175]

Answer:

Also, as stream depth increases, the hydraulic radius increases thereby making the stream more free flowing. Both of these factors lead to an increase in stream velocity. The increased velocity and the increased cross-sectional area mean that discharge increases.

8 0
3 years ago
Calculate the electric potential energy in a capacitor that stores 4.0 10-10 C of charge at 250.0 V
Arada [10]
Q = C.v
v = Q/C
v = 4 × 10^(-10)/250
 = 4 × 10^(-10)/2.5 × 10^2
 = 1.6 × 10^(-12) volt
7 0
3 years ago
Read 2 more answers
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