F=ma
11.6=3.8*a
a=11.6/3.8
a=3.05m/s
Answer:
Fa=774 N
Fb=346 N
Explanation:
We will solve this problem by equating forces on each axis.
- On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
- On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative
While towing we know that car is mot moving in y-direction so net force in y-axis must be zero
⇒∑Fy=0
⇒![Fa*sin(50)-Fb*sin(20)=0](https://tex.z-dn.net/?f=Fa%2Asin%2850%29-Fb%2Asin%2820%29%3D0)
⇒![Fa*sin(50)=Fb*sin(20)](https://tex.z-dn.net/?f=Fa%2Asin%2850%29%3DFb%2Asin%2820%29)
⇒![Fa=2.24Fb](https://tex.z-dn.net/?f=Fa%3D2.24Fb)
Given that resultant force on car is 950N in positive x-direction
⇒∑Fx=950
⇒![Fa*cos(20)+Fb*cos(50)=950](https://tex.z-dn.net/?f=Fa%2Acos%2820%29%2BFb%2Acos%2850%29%3D950)
⇒![2.24*Fb*cos(20)+Fb(50)=950](https://tex.z-dn.net/?f=2.24%2AFb%2Acos%2820%29%2BFb%2850%29%3D950)
⇒![Fb*(2.24*cos(20)+cos(50))=950](https://tex.z-dn.net/?f=Fb%2A%282.24%2Acos%2820%29%2Bcos%2850%29%29%3D950)
⇒![Fb=\frac{950}{2.24*cos(20)+cos(50)}](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.24%2Acos%2820%29%2Bcos%2850%29%7D)
⇒![Fb=\frac{950}{2.24*0.94+0.64}](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.24%2A0.94%2B0.64%7D)
⇒ ![Fb=\frac{950}{2.75}=345.5](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.75%7D%3D345.5)
⇒![Fa=2.24*Fb](https://tex.z-dn.net/?f=Fa%3D2.24%2AFb)
![=2.24*345.5](https://tex.z-dn.net/?f=%3D2.24%2A345.5)
![=773.93](https://tex.z-dn.net/?f=%3D773.93)
Therefore approximately, Fa=774 N and Fb=346 N
The correct option is B.
Sunglasses are designed to block polarized light. If you are driving toward the sun, most of the sun's glare will be coming to you horizontally, thus, the best sunglasses to wear is the one, that will block the horizontal glare and allow only the vertical glare to pass through.
The mass is still 10 kg. But instead of weighing 98N as it does on Earth, it weighs 245N on Jupiter.
Answer:
v = 4.18 m/s
Explanation:
given,
frequency of the alarm = 872.10 Hz
after passing car frequency she hear = 851.10 Hz
Speed of sound = 343 m/s
speed of the jogger = ?
speed of the
![v_f = \dfrac{872.10-851.10}{2}](https://tex.z-dn.net/?f=v_f%20%3D%20%5Cdfrac%7B872.10-851.10%7D%7B2%7D)
![v_f =10.5\ Hz](https://tex.z-dn.net/?f=v_f%20%3D10.5%5C%20Hz)
v_o = 872.1 - 10.5
![V_0 = 861.6\ Hz](https://tex.z-dn.net/?f=V_0%20%3D%20861.6%5C%20Hz)
The speed of jogger
![v = \dfrac{v_1 \times 343}{v_0}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bv_1%20%5Ctimes%20343%7D%7Bv_0%7D-343)
![v = \dfrac{872.1 \times 343}{861.6}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B872.1%20%5Ctimes%20343%7D%7B861.6%7D-343)
v = 4.18 m/s