Answer:
And the force of ( Attraction or repulsion) between the poles A and D ( maximum or minimum)
Air expands as it warms. Therefore warm air is less dense than cool air. The warm air from the first floor apartments rises to the second floor. People on the second floor require less heating to keep their <span>apartments comfortable.
-Hope this helps </span>
Answer:
linear charge density = -9.495 ×
C/m
Explanation:
given data
revolutions per second = 1.80 ×
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 ×
×
q = m × w² × r ............2
and w =
w =
w = 1.80 ×
×
w = 11304000 rad/s
so here from equation 2
- 9 ×
×
1.80 ×
= 1.672 ×
× 11304000² × 0.0120
linear charge density = -9.495 ×
C/m
Answer:
Work done, W = 1786.17J
Explanation:
The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "
Mass of a painter, m = 75 kg
He climbs 2.75-m ladder that is leaning against a vertical wall.
The ladder makes an angle of 30 degrees with the wall.
We need to find the work done by the gravity on the painter.
The angle between the weight of the painter and the displacement is :
θ = 180 - 30
= 150°
The work done by the gravity is given by :

Hence, the required work done is 1786.17 J.