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azamat
3 years ago
8

Shawn and his bike have a total mass of

Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, m=52.3\ kg

Displacement of the bike is, d=1.6\ km=1.6\times 1000=1600\ m

Time taken is, t=17.4\ min=17.4\times 60=1044\ s

Let the constant velocity be v.

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s

Now, kinetic energy of a body is given as:

KE=\frac{1}{2}mv^2

Here, m=52.3\ kg,\ v=1.533\ m/s

\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J

Therefore, Shawn's kinetic energy is 61.45 J.

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Answer:

± (.021 ) ohm

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Ashley squirrel, named Jackie, rides on a bicycle with a constant kinetic energy of 3.6J. The mass of combination of Jackie and
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The velocity of the combination of Jackie and the bicycle is 3.328 m/s.

Explanation:

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KE = 0.5 x mv2.

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3 years ago
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Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance
NemiM [27]

Answer:

Explanation:

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F = k q₁ q₂ / d₂

Here force between charge q₁ = - 15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = (1.66 - 1.24 ) = .42 mm

k = 1/ 4π x 8.85 x 10⁻¹²

putting the values in the expression

F = 1/ 4π x 8.85 x 10⁻¹²  x - 15 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

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= 35969.4 x 10⁻³ N .

force between charge q₂ =  34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = ( 1.24 - 0 ) = 1.24 mm .

putting the values in the expression

F = 1/ 4π x 8.85 x 10⁻¹²  x  34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

= 9 x 10⁹ x  - 34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

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5 0
3 years ago
In this problem, we want to represent the relationship between the input of a system, x, and its output, y, using a polynomial.
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clc

clear all

close all

format long

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function [z,N,R2]=polyfitsystem(x,y,R2)

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