Answer:
this makes no since so i cant help you here sorry
Mass and distance are the two factors
S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)
S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m
Distance double 720m*2=1440m
V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
Answer:
Energy required = 3169.34 Joules.
Explanation:
The quantity of energy (Q) required can be determined by;
Q = mcΔθ
Where: m is the mass, c is the specific heat and Δθ is the change in temperature.
But, m = 96.7 kg, c = 0.874 J/(kg
), 
= 
and 
= 
.
So that,
Q = mc( - )
= 96.7 x 0.874 x ( - )
= 96.7 x 0.874 x 37.5
= 3169.3425
Q = 3169.34
= 3.2 KJ
The amount of energy required is 3169.34 Joules.
Answer:
The gravitational acceleration of the planet is, g = 8 m/s²
Explanation:
Given data,
The distance the object falls, s = 144 m
The time taken by the object is, t = 6 s
Using the III equations of motion
S = ut + ½ gt²
∴ g = 2S/t²
Substituting the given values,
g = 2 x 144 /6²
= 8 m/s²
Hence, the gravitational acceleration of the planet is, g = 8 m/s²
