Answer:
Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.
Now length of the rod along the direction of motion
= lo cos 60°_/1-(0.8) 2/c2
= lo/2×0.6
= 0.3 lo.
Length of the rod perpendicular to the direction of motion.
= lo sin 60°
=_/3/2 lo
Length of moving rod
l = [(0.3lo)2+{lo_/3/2} 2] 1/2
= 0.916 lo.
Percentage contraction
= lo-0.916lo/lo×100
= 8.4%.
Explanation:
<h2><u><em>
Brainliest?</em></u></h2>
My workout schedule is day on - day off
This helps the body rest after the work out and let it gain/build muscle mass
Good luck
Answer:
10.84 m/s2 radially inward
Explanation:
As the car is traveling an a constant tangential speed of 80.8 m/s, the total acceleration only consists of the centripetal acceleration and no linear acceleration. The formula for centripetal acceleration with respect to tangential speed v = 80.8 m/s and radius r =602 m is
b) The direction of this centripetal acceleration is radially inward
Answer:
Momentum of mass 
is 83·7 kg m/s towards north
Momentum of mass 
is 38·72 kg m/s towards east
Explanation:
Given
Mass of = 6·2 kg
Mass of = 4·4 kg
Velocity of mass = 
= 13·5 m/s
Velocity of mass = 
= 8·8 m/s
Momentum of mass = × = 6·2 × 13·5 = 83·7 kg m/s
Momentum of mass = × = 4·4 × 8·8 = 38·72 kg m/s
As mass is moving North, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity
As mass is moving East, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity
∴ Momentum of mass is 83·7 kg m/s towards north
∴ Momentum of mass is 38·72 kg m/s towards east
