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icang [17]
3 years ago
13

Relating the circumference to the force applied on the balloon, make a conclusion on the relationship of force to the rate of th

e change of motion of the balloon at a constant mass.​
Physics
1 answer:
natka813 [3]3 years ago
3 0

At a constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

The force applied to an object can be determined by applying Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

where;

  • <em>m is the mass of the balloon</em>
  • <em>a is the change in velocity per time</em>

F = m\frac{\Delta v}{t} \\\\\frac{F}{\frac{\Delta v}{t}} = m

The mass of an object is inversely proportional to the rate of change motion of the object.

Thus, we can conclude that at constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

Learn more here:brainly.com/question/15321240

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A body has weight 600N on the surface of the mars then what is its mass on the same place.​
laiz [17]

Answer:

\boxed{m = 162.16 kg}

Explanation:

<u><em>Given:</em></u>

Weight = W = 600 N

Acceleration due to gravity = g = 3.7 m/s²

<u><em>Required:</em></u>

Mass = m = ?

<u><em>Formula:</em></u>

W = mg

<u><em>Solution:</em></u>

For m, it'll be

=> m = W/g

=> m = 600/3.7

=> m = 162.16 kg

5 0
3 years ago
Read 2 more answers
16 points and brainiest whoever is right
masha68 [24]
Let k be the spring constant. Then you have
188=k*21.8
k=188/21.8=8.62,
In the second part you use
m g= k x
x=m g/k= 38/8.62=4.4cm

4.4 cm is the answer
6 0
4 years ago
(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5
Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}

a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Put the value into the formula

\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}

\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s

The energy in ev/s

\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s

\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s

We need to calculate the fraction of its energy that it radiates every second

\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}

\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}

Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

5 0
3 years ago
When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe
sattari [20]

Answer:A

Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.

3 0
3 years ago
!!!!!!ASAP!!!!!!!
elena-s [515]
Answer
18,000

Why?
KE=(1/2)(2000)(18)
Ke=18,000
8 0
2 years ago
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