Answer:
The concentration of acetic acid present in the vinegar is 0.113M
Explanation:
1. As the titration occurs between an acid and a base is called neutralization. The balanced chemical reaction between the acetic acid and the NaOH is:
2. Calculate the moles of NaOH used, taking in account the concentration of NaOH 1.00M:
3. Calculate the number of moles of acetic acid neutralized using stoichiometry:
4. Calculate the concentration of acetic acid present in the vinegar:
Answer:
(a) t = 0 s
(b) t = 0 s, 30 s, 55 s
(c) t = 40 s to t = 60 s
(d) t = 10 s to t = 15 s
(e) a = 6 m/s^2
Explanation:
(a) The car is at starting position at t = 0 s and v = 0 m/s.
(b) The velocity of car is zero when the time is t = 0 s, 30 s and 55 s.
(c) from t = 40 s to 60 s the car is moving in the negative direction.
(d) The fastest speed is 60m/s from t = 10 s to t = 15 s.
(e) The slope of the velocity time graph gives acceleration.
a = (60 - 0) / (10 - 0) = 6 m/s^2
Answer:
91.21
Explanation:
Kinetic energy =1/2 mv2 substitute the values I. E 1/2 *1 *4.5^2= 91.21
Answer:
khoảng cách = 8km / h
Explanation:
khoảng cách = tốc độ / thời gian
khoảng cách = 12/40
khoảng cách = 8km / h
