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fomenos
3 years ago
10

How does the law of conservation of energy relate to the system shown in this model

Physics
2 answers:
Svetach [21]3 years ago
6 0

Answer:

the sun gives off energy to the color panel

egoroff_w [7]3 years ago
3 0

Answer: The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system.

Explanation:

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(a) What is the cost of heating a hot tub containing 1440 kg of water from 10.0°C to 40.0°C, assuming 75.0% efficiency to take h
BaLLatris [955]

Answer:

a) E = 6.024\,USD, For m kilograms, it is 4184m J., 3600000 joules, b) i = 88.200\,A

Explanation:

a) The amount of heat needed to warm water is given by the following expression:

Q_{needed} = m_{w}\cdot c_{w}\cdot (T_{f}-T_{i})

Where:

m_{w} - Mass of water, measured in kilograms.

c_{w} - Specific heat of water, measured in \frac{J}{kg\cdot ^{\circ}C}.

T_{f}, T_{i} - Initial and final temperatures, measured in ^{\circ}C.

Then,

Q_{needed} = (1440\,kg)\cdot \left(4184\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (40^{\circ}C - 10^{\circ}C)

Q_{needed} = 180748800\,J

The energy needed in kilowatt-hours is:

Q_{needed} = 180748800\,J\times \left(\frac{1}{3600000}\,\frac{kWh}{J} \right)

Q_{needed} = 50.208\,kWh

The electric energy required to heat up the water is:

E = \frac{50.208\,kWh}{0.75}

E = 66.944\,kWh

Lastly, the cost of heating a hot tub is: (USD - US dollars)

E = (66.944\,kWh)\cdot \left(0.09\,\frac{USD}{kWh} \right)

E = 6.024\,USD

The heat needed to raise the temperature a degree of a kilogram of water is 4184 J. For m kilograms, it is 4184m J. Besides, a kilowatt-hour is equal to 3600000 joules.

b) The current required for the electric heater is:

i = \frac{Q_{needed}}{\eta \cdot \Delta V \cdot \Delta t}

i = \frac{180748800\,J}{0.75\cdot (220\,V)\cdot (3.45\,h)\cdot \left(3600\,\frac{s}{h} \right)}

i = 88.200\,A

7 0
3 years ago
Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a ma
andrezito [222]

Question:

Consider a sample of helium gas in a container fitted with a piston as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I. Heating the helium. II.

II. toRemoving some of the helium from the container.

III. Turning the container on its side.

IV. Decreasing the pressure outside the container.

a) 0

b) 1

c) 2

d) 3

e) 4

Answer:

Only one process will cause the piston to move which is

i) Heating the helium

Explanation:

When helium is heated it becomes less dense or lighter. Heating the helium will cause an increase in volume which will make the piston to move away from the base. When the volume finishes increasing, the piston will stop moving which in turn will make the forces on both sides of the piston balanced, so the pressure inside will balance the weight of the piston and that of the atmosphere. From that we can see that there has been a pressure change as a result of heating.

6 0
3 years ago
Read 2 more answers
What parts are found in an electric generator
Len [333]

Here are a list of items I found.

some brushes

a armature

a permanent magnet

some slip rings

3 0
3 years ago
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What are the 3 Newton's law of motions?
irinina [24]

Answer:

laws of motion relate an object’s motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

4 0
2 years ago
Mechanical energy is lost:
9966 [12]
3. Due to the fact that friction is not converted to kinetic energy nor potential energy. The energy is converted into heat energy which is lost and can’t be put back
7 0
2 years ago
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