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7nadin3 [17]
3 years ago
12

Sam has been working to improve his muscular fitness. He jumps rope and trains with weights. What will most likely be the result

of Sam's efforts?
Physics
2 answers:
irina [24]3 years ago
7 0

Answer:

increase bone density

Explanation:

Sam in an effort to improve his muscular fitness jumps rope and trains weights. The result of the Sam's effort would his increased bone density.

Several research have shown a positive impact of exercise on bone density.A regular Pelvic exercise for 30 days increase the hip bone density significantly.

Similar is case of other exercises as well. Doctors recommend exercise to improve bone mass density

const2013 [10]3 years ago
4 0
Increased Bone Density
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A 400.0-m-wide river flows from west to east at 30.0 m/min. Your boat moves at 100.0 m/min relative to the water no matter which
Ratling [72]

Answer:

a. boat would drift towards a NE direction

b. 104.4m/min * t

c. false

d. point downstream of c, -79.19 deg NE

e. 3.898mins

f. 389.8m

Explanation:

a. downstream is a location with respect to the direction of the flow of the river, in this case from west to east. the boat would drift towards the NE direction due to the direction of water current.

b. lets say it takes time t to travel across the river, the resultant speed of boat would be given as Rs= sqrt ( 100/min^2 + 30m/mins^2) = 104.4m/mins

distance traveled would be 104.4 *t

c. false, the direction of boat wouldnt remain perpendicular the entire crossing but would drift toward the NE bearing provided the driver doesnt change or steer the boat.

d. a. taking the definition of downstream in question (a), your boat would land at a point x downstream to c

   b. to land at c boat must be inclined at an angle of -79.19 deg NE, given by using the width of river and the distance of b to c.

                            cosФ= 75/ 400

                                  Ф= 79.19°NE to get to c you must position boat at an angle of -79.19 deg from your initial bearing.

e. speed = distance/ time, time = distance / speed.

aiming toward point c, speed of boat is the resultant speed of boat with respect to the speed of water, using Pythagoras also

speed=  \sqrt{ 100^{2} + 30^{2} } = 104m/mins

distance to move from point a to c is given also given by

distance = \sqrt{400^{2} + 75^{2} }= 406.97m

time = 406.97/ 104.4 = 3.89mins...

f. on the ground the observer see the boat speed as 100m/min.

distance traveled is given by speed * time= 100 * 3.89= 389m

g. speed of boat observed would be 100m/min

5 0
3 years ago
A(n) 0.47 kg softball is pitched at a speed of 10 m/s. The batter hits it back directly at the pitcher at a speed of 29 m/s. The
nadya68 [22]

Answer:

18.33 Ns

Explanation:

As the pitch back speed has the opposite direction as before, the change in velocity would be

\Delta v = v_2 - v_1 = 29 - (-10) = 39 m/s

So the change in momentum of the ball would be the product of its velocity change and its mass

\Delta p = \Delta v m = 39 * 0.47 = 18.33 kgm/s

This is equals to the impulse acted on the ball by the bat, which is 18.33 Ns

8 0
2 years ago
A 25 kg child runs at a speed of 5.0 m/s and jumps onto a stationary shopping cart and holds on for dear life. The cart has mass
makkiz [27]

Answer:

3.38 m/s

Explanation:

Mass of child = m₁ = 25

Initial speed of child = u₁ = 5 m/s

Initial speed of cart = u₂ = 0 m/s

Mass of cart = m₂ = 12 kg

Velocity of cart with child on top = v

This is a case of perfectly inelastic collision

m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\frac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\frac{25\times 5+12\times 0}{25+12}\\\Rightarrow v=\frac{125}{37}\\\Rightarrow v=3.38\ m/s

Velocity of cart with child on top is 3.38 m/s

7 0
3 years ago
A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity
olga_2 [115]

Answer:

The velocity of the rocket is 7.8 m/s

Explanation:

3 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Anon25 [30]

In several of the questions you've posted during the past day, we've already said that a wave with larger amplitude carries more energy.  That idea is easy to apply to this question.

8 0
3 years ago
Read 2 more answers
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