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KonstantinChe [14]
4 years ago
5

Need answers ASAP!!!!

Mathematics
1 answer:
ch4aika [34]4 years ago
4 0

I thought we didn't get the choices, but they were cropped on my screen.  Let's see how I did.

Prism length L, width W, height H, volume V=LWH    [they used small letters, but ok]

Parallelogram, base b, height h, area A=bh  [good]

Circumference C of a circle radius r, C=2πr  [bad guess,

they had diameter d, so C=πd]

Area A of a circle radius r, A = πr²  [good]

Area A of a triangle, base b, height h, A = (1/2) bh   [good]

Area A of a trapezoid, bases a,b, height h, A= (1/2)(a+b)h

 [good, they notated it with subscripts on the base.]

Perimeter p of a quadrilateral sides a,b,c,d   p=a+b+c+d

[They did a rectangle or parallelogram; I did the general quadrilateral.  The answer they're looking for is 2L+2W.]


I'm guessing of course.  My favorite formula for the area S of a triangle with squared sides A, B and C is

16S^2 = 4AB-(A+B-C)^2

and I want to go to the school that puts that one on the test.


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SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!
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Answer:

-3f - 10

Step-by-step explanation:

-1 times 10 = -10

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Sorry if this isn't right.

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3 years ago
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You deposit $3000 into a money-market savings account which pays 4.8% compounded quarterly, and you make no withdrawals from or
faust18 [17]

Answer:

$5265.71

Step-by-step explanation:

We have been given that you deposit $3000 into a money-market savings account which pays 4.8% compounded quarterly.

We will use future value formula to solve our given problem.

FV=C_0\times (1+r)^n, where,

C_0=\text{Initial amount},

r = Rate of return in decimal form,

n = Number of periods.

4.8\%=\frac{4.8}{100}=0.048

n=3\times 4=12

FV=\$3,000\times (1+0.048)^{12}

FV=\$3,000\times (1.048)^{12}

FV=\$3,000\times 1.7552354909370114

FV=\$5265.7064\approx \$5265.71

Therefore, there will be $5265.71 in your account at the end of those 3 years.

8 0
4 years ago
A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
The heavyweight weight class in high school wrestling is from no less than 195lb and a maximum 285 LB write two inequalities to
rewona [7]

Answer:

<em>w >= 195 and w <= 285</em>

Step-by-step explanation:

No less than 195 lb means that 195 lb or more is allowed.

Let w = weight.

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Answer:  w >= 195 and w <= 285

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4 years ago
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