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vovikov84 [41]
3 years ago
14

What are the vertical rows on the periodic table called?

Chemistry
1 answer:
MatroZZZ [7]3 years ago
5 0
Vertical rows are called GROUPS on periodic table.....
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A cube of tin that is 112 mm on each side has a mass of 8.21 grams. A single tin atom has a mass of 118.7 amu. How many tin atom
Sveta_85 [38]

Answer:

4.17e+22 atoms of tin are present in the cube

Explanation:

We don't require the size of the cube. With the mass and the molar mass of tin = 118.7 amu we can find moles of Tin. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:

<em>Moles Tin:</em>

8.21g * (1mol / 118.7g) = 0.0692 moles Tin

<em>Atoms Tin:</em>

0.0692 moles Tin * (6.022x10²³ atoms / mol) =

<h3>4.17e+22 atoms of tin are present in the cube</h3>
5 0
3 years ago
Which change is most likely to occur when a molecule of H2 and a molecule of I2 collide with proper orientation and sufficient e
bazaltina [42]
The collision of the molecules between the hydrogen molecule or H2, and an iodine molecule or I2, provided there would be a sufficient energy is that the system would eventually undergo a chemical change wherein a new chemical compound would be formed from these two molecules.
8 0
3 years ago
Read 2 more answers
Calculate the boiling temperature of a 0.50 M solution of sucrose. Assume that the concentration is 0.50 m.
Ronch [10]
There is one missing point in the question.

The formula to find an increase in boiling Temperature is :

ΔT = kb x M

ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity

You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.


And assuming that the other solution is water, you just have to add it up with 100 Celcius


5 0
3 years ago
Pablo drove 260 miles using 12 gallons of gas. at this rate, how many gallons of gas would he need to drive 286 miles?
Naddik [55]
260 miles with 12 gallons of gas
260 miles/12 gallons=21.6667 miles/1 gallon
286 miles/(21.6667 miles/1 gallon)=13.2 gallons of gas
7 0
4 years ago
Linda performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0
nexus9112 [7]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

To calculate the amount of heat absorbed or released, we use the following equation:

q=mc\Delta T    .....(1)

where, q = amount of heat absorbed or released.

m = mass of the substance

c = heat capacity of  water = 4.186 J/g ° C      

\Delta T = Change in temperature

  • <u>For Trial 1:</u>

We are given:

m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J

Putting values in equation 1, we get:

q=30g\times 4.186J/g^oC\times 40^oC

q = 5023.2 J

  • <u>For trial 2:</u>

We are given:

m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J

Putting values in equation 1, we get:

q=40g\times 4.186J/g^oC\times 10^oC

q = 1674.4 J

Heat gained by Trial 1 than trial 2 = (5023.2-1674.4)J=3347J

Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.

Thus, the correct answer is Option b.

4 0
3 years ago
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