Cacl2 dissolve in water according to the following equation
Cacl2 + H2O = Ca(OH) + Hcl
Volume= moles/molarity
The reacting ratio between CaCl2 to Ca(OH) is 1:1
therefore moles of solution is also 0.0262 moles hence volume is =
0.0262mol/ 0.52mol/l = 0.0504L or50.4ml
answer:
in plants
Transport manufactured food from the leaves to others parts of the plant
Facilitates gaseous exchange through the stomata in the leaves to other parts of the plant
in animal
Exchange of respiratory gases across respiratory services
Excretion of nitrogenous waste in some unicellular organisms
Explanation:
Hope it benefit
Answer:
molarity of acid =0.0132 M
Explanation:
We are considering that the unknown acid is monoprotic. Let the acid is HA.
The reaction between NaOH and acid will be:
Thus one mole of acid will react with one mole of base.
The moles of base reacted = molarity of NaOH X volume of NaOH
The volume of NaOH used = Final burette reading - Initial reading
Volume of NaOH used = 22.50-0.55= 21.95 mL
Moles of NaOH = 0.1517X21.95=3.33 mmole
The moles of acid reacted = 3.33 mmole
The molarity of acid will be = 
I think the answer might be 51.14% since the formula had to equal a 100% just add 41.86 and 6.98 and subtract the sum to 100.
