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Goshia [24]
3 years ago
13

A) How much CO is required for the production of Fe from 1000 tonnes of magnetite (Fe2O4). Assume that the iron ore is 100% pure

.
B) How many kilograms of iron should be produced?

C) If the reaction yielded 555 kg of Fe, what is the percentage yield for the process
Chemistry
1 answer:
Kryger [21]3 years ago
5 0
Its b im pretty sure
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At elevated temperatures, sodium chlorate decomposes to produce sodium chloride and oxygen gas. A 0.8765-g sample of impure sodi
barxatty [35]

Answer:

z = 18,46%

Explanation:

First we need to discover the mole number of the O2 produced so we use PV=nRT

734 torr * 57.2*10^-3 L = n 62.3637 * 295.15 K

n = \frac{734 * 57.2*10^-3}{62.3637 * 295.15}

n = \frac{41,98}{18.406}

n = 2,28 * 10^-3 mole

The reaction to the decomposition is:

2 NaClO3 --> 2 NaCl + 3 O2

2 mole NaClO3 - 3 moles O2

x - 2,28*10^-3 moles O2

X= 1,52*10^-3 moles of NaClO3

1 moles of NaClO3 - 106,44 g

1,52*10^-3 moles of NaClO3 - y

y = 0,1617 g

0,8765 g - 100%

0,1617 g - z

z = 18,46%

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3 years ago
An atom that has the same number of neutrons as ba is:.
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The symbol is ba. The number of neutrons equal the number of protons

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) What is the definition of an enzyme? A.Enzymes are carbohydrate molecules that act as catalysts to speed up chemical reactions
DochEvi [55]

Answer:

option c

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4 years ago
What is the concentration of a solution of HCl in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutraliza
puteri [66]

Answer:

The answer is 0.75M HCl

Explanation:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

C1V1 = C2V2

C1 = concentration of acid

C2 = concentration of base

V1 = volume of acid

V2 = volume of base

From the information supplied in the question:

concentration of acid (HCl) is the unknown

volume of acid (HCl) = 10ml

concentration of base (NaOH) = 0.15M

volume of base (NaOH) = 50ml

C1 x 10ml = 0.15M x 50ml

C1 x 10 = 7.5

divide both side by 10

C1 = 0.75M

concentration of acid (HCl) is 0.75M

5 0
3 years ago
NEED HELP ASAFP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!PLEASE!
sp2606 [1]
Here to help! What’s up?
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