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omeli [17]
3 years ago
12

Please help with 1 and 4

Physics
1 answer:
KIM [24]3 years ago
5 0
Number 4 is : a light hour is a measure of time in space used to calculate the length of time between one object to another and one light hour equals 1.079 × 109 kilometers or 1.079e+9
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Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de
Vesnalui [34]

Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 \frac{m}{s}

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa.  Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido,  en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

  • A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.
  • v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4} , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2

En este caso:

  • D1: 0.06 m
  • v1: ?
  • D2: 0.04 m
  • v2: 2.6 m/s

Reemplazando:

\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}

Resolviendo:

v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}

v1=\frac{(0.04m)^{2} }{(0.06m)^{2}  }*2.6\frac{m}{s}

v1= 1.156 \frac{m}{s}

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u>\frac{m}{s}<u><em></em></u>

8 0
3 years ago
If a wave’s frequency is 16Hz and it’s wavelength is 10m. What’s the waves speed?
Vesna [10]

Answer:

160J

Explanation:

Given parameters:

Frequency  = 16Hz

Wavelength = 10m

Unknown:

Waves speed  = ?

Solution:

Waves speed is the product of frequency and wavelength;

  Waves speed  = fλ

f is the frequency

λ is the wavelength

Now insert the parameters and solve;

     Waves speed = 16 x 10  = 160J

4 0
3 years ago
When you rub a balloon on a sweater or your hair, the what is transferred to the balloon giving it a what charge. The balloon wi
Elis [28]

Answer:

When you rub a balloon on a sweater or your hair, the <u>electrons</u> are transferred to the balloon giving it a <u>negative</u> charge. The balloon will then <u>repel</u> any object that has a different charge.

hope this helps :)

5 0
3 years ago
In a given neuron, the current membrane potential is 60 mv. what does this tell you about the current potential compared to the
alekssr [168]

The membrane is depolarized compared to the resting membrane potential.

Through conformational changes from closed, nonconducting states to an open, current-conducting state, membrane depolarization activates sodium channels. Na+ channels open slowly and change from an open state to a nonconducting, rapidly inactivated state as a result of delayed openings, which contribute to the declining fraction of INa induced by prolonged depolarization. Additionally, sodium channels can move swiftly from the closed state to the fast-inactivated state. When the membrane is depolarized, inactivated channels are prevented from opening.

The distribution of channels between the closed and slow-inactivated states, however, limits the number of excitable sodium channels as a function of the membrane potential since slow inactivation acts at greater negative potentials than fast inactivation.

To learn more about membrane potential please visit-
brainly.com/question/8438145
#SPJ1

3 0
2 years ago
Why does a batsman striking a cricket ball follow through?​
Over [174]

A good follow-through maintains flow in the motion. It is to hit 'smooth', rather than to hit 'hard'. It is to maintain a certain 'looseness' in the swing, rather than 'tension' or 'over-hitting' the ball with too much power.

5 0
3 years ago
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