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blondinia [14]
2 years ago
7

VECTORS HELP~~

Physics
1 answer:
Korolek [52]2 years ago
6 0

<span>R² = 12² + 4² - 2*12*4cos45° </span>
<span>R² = 92.12 </span>
<span>R = 9.6 mph ===========> ANSWER </span>

<span>Use law of sines to find bearing </span>
<span>4/sinA = R/sin45° </span>
<span>sinA = 4sin45°/9.6 = 0.2946278...... </span>
<span>A = 17.14° </span>
<span>bearing = North 17.14° West or 342.86°</span>
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You have two points in a soil. Point A is at 75 cm; point B is at 25 cm above the reference. The capillary potential energy at p
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Answer:

The potential energy at point A is 17.1675 J

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The capillary potential is the work expended to bring up a unit mass of liquid to a point in a capillary region from a level liquid surface. It is the capillary potential that facilitates the movement of moisture within soil capillaries

In meteorology it is used to describe the level of saturated soil above the water table

Potential energy is the energy inherent in a body by virtue of its position, therefore the potentials of both point A and B are

Point A, elevation = 75 cm capillary potential = -100 cm

Point B, elevation = 25 cm capillary potential = -200 cm

The total potential energy at point A is

Elevation above reference - capillary potential =75-(-100) = 175 cm

which gives per unit mass

PE = m × g × h = 1 kg × 9.81 m/s ² × 1.75 m = 17.1675 kg·m²/s² = 17.1675 J

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