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AysviL [449]
3 years ago
12

The electrostatic force between two charges located 2 meters apart is 0.10 N. What will the force be between these charges when

they are located 1 meter apart?
Physics
1 answer:
Vikentia [17]3 years ago
6 0
Given that 2 m is to .10N

we will set up a ratio & proportion

.10 x
— —
2 1

cross multiply

2x = .10(1)

divide both sides by 2

x (and the answer) = .05 N

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(30 points) Air at 500 kPa and 400 K enters an adiabatic nozzle at a velocity of 30 m/s and leaves at 300 kPa and 350 K. Using v
Sophie [7]

Answer:

Explanation:

Check attachment for solution

8 0
3 years ago
In a pig-calling contest, a caller produces a sound with an intensity level of 60 db. how many such callers would be required to
zloy xaker [14]

The imaginary second level is 60 dB more intense than the real level of the caller.

60 dB means a multiplication of  10⁶  = <em>1 million.</em>

That's how many equally-talented callers it would take to be 60 dB louder than him.

7 0
3 years ago
in california the pacific plate slides past the north american plate. If the pcific plate is moving at a speed of 5 centimeters
frozen [14]

Answer:

6.34×10⁹ seconds

Explanation:

Applying,

V = d/t............. Equation 1

Where V = speed plate, d =  distance covered by the plate, t = time it takes the plate to travel

make t the subject of the equation

t = d/V............ Equation 2

From the question,

Given: d = 5 cm/yr = (5×3.154×10⁻⁹) = 1.577×10⁻⁸ m/s,  d = 100 meter

Substitute these values into equation 2

t = 100/1.577×10⁻⁸

t = 6.34×10⁹ seconds

Hence the time it takes the the plate to travel is 6.34×10⁹ seconds

3 0
3 years ago
A train consists of a caboose (mass = 1000 kg), a car (mass 2000 kg), and an engine car (mass 2000 kg). If the train has an acce
Veseljchak [2.6K]
Mass of caboose 1000 kg
mass of caboose plus mass of middle car = 3000 kg
a = 5

F = ma
3000 * 5 = 15.000 N

hope this help
7 0
4 years ago
Read 2 more answers
A light wave with an electric field amplitude of E0 and a phase constant of zero is to be combined with one of the following wav
Anarel [89]

Answer:

the greatest intensity is obtained from   c

Explanation:

An electromagnetic wave stagnant by the expression

           E = E₀ sin (kx -wt)

when two waves meet their electric fields add up

           E_total = E₁ + E₂

the intensity is

           I = E_total . E_total

           I = E₁² + E₂² + 2E₁ E₂ cos θ

where θ  is the phase angle between the two rays

       

Let's examine the two waves

in this case E₁ = E₂ = E₀

          I = Eo2 + Eo2 + 2 E₀ E₀ coasts

         I = E₀² (2 + 2 cos θ )

         I = 2 I₀ (1 + cos θ )

     let's apply this expression to different cases

a) In this case the angle is zero therefore the cosine is worth 1 and the intensity is I_total = 4 I₀

b) cos π = -1     this implies that     I_total = 0

c) the cosine is  1,

         I = E₀² + 4E₀² + 2 E₀ (2E₀) cos θ

         I = E₀² (5 +4 cos θ)

         I = E₀² 9

         I = 9 Io

d) in this case the cos pi = -1

          I = E₀² (5 -4)

          I = I₀

e) we rewrite the equation

         I = E₀² + 9 E₀² + 2 E₀ (3E₀) cos θ

         I = Eo2 (10 + 6 cos θ)

         cos π = -1

         I = E₀² (10-6)

         I = 4 I₀

the greatest intensity is obtained from   c

3 0
3 years ago
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