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Ronch [10]
3 years ago
13

Describe the end behavior of the function.

Mathematics
2 answers:
slega [8]3 years ago
7 0
C is the correct answer.
Aleksandr [31]3 years ago
5 0
As x goes to infinity, f(x) approaches negative infinty
as x oes to  negative infinity, f(x) approaches 0


C is answer
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Given that sinФ = 8/17 and cos Ф < 0:
Gekata [30.6K]

Answer:

1) The terminal side lies in quadrant 2

2) cosФ = -15/17

3) tanФ = -8/15

Step-by-step explanation:

1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1

2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17

3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15

6 0
3 years ago
2-10n more math homework :|
creativ13 [48]

Step-by-step explanation:

Yea we need more information.

4 0
3 years ago
Choose the inequality that represents the following graph (ANSWER ASAPP PLEASE)
Makovka662 [10]
B - Since it is a dotted inequality, it would be a equal to and something else. And since it is greater than 3, it would be X is equal to or less than 3
5 0
3 years ago
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Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
Help<br>evaluate 12-3×2+1​
Feliz [49]

Answer:

7 hope this helps(✿◠‿◠)

Step-by-step explanation:

5 0
3 years ago
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