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omeli [17]
4 years ago
14

Solve for x, given the equation Square root of x minus 5 + 7 = 11.

Mathematics
2 answers:
marin [14]4 years ago
8 0

Answer:  The required solution is x = 21.

Step-by-step explanation:  We are given to solve the following equation for x :

"Square root of x minus 5 + 7 = 11."

The given equation can be written and solved as follows :

\sqrt{x-5}+7=11\\\\\Rightarrow \sqrt{x-5}=11-7\\\\\Rightarrow \sqrt{x-5}=4\\\\\Rightarrow x-5=4^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow x-5=16\\\\\Rightarrow x=16+5\\\\\Rightarrow x=21.

Thus, the required solution is x = 21.

Solnce55 [7]4 years ago
4 0
X= 9 is the answer to this question
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arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

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(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

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2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

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5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

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Answer: 972 x^16 y^24

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