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3 years ago

Sally has 2/8 cookies in a jar she ate 1/4 how many dose she have left :explain

Mathematics

1 answer:

kati45 [8]3 years ago

4 0

Answer:

1.5 cookies if 2/8 is like 2 cookies out of 8, 1/16 if its like 2/8 of a cookie

Step-by-step explanation: \

1.5: 2 x 3/4 (already ate 1/4) = 1.5

1/16= 1/4 (2/8 reduced) x 1/4

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Find a quadratic equation whose roots are 1.5 +√2 and 1.5-√2expressing it in the form of ax^2+bx+c+c=0 where a,b and c are integ

Ilia_Sergeevich [38]

0 = f(x) = (x - r)(x - s) = x² - (r+s) + rs

We have r=1.5+√2, s=1.5 -√2 so r+s = 3 and

rs = (1.5+√2)(1.5 - √2) = 1.5² - (√2)² = 2.25 - 2 = 0.25

f(x) = x² - 3x + -.25

For integer coefficients we mulitply by 4,

g(x) = 4f(x) = 4x² - 12x - 1

Answer: 4x² - 12x - 1 = 0

5 0

3 years ago

20 Point!

ludmilkaskok [199]

determinant: $\sqrt{b^2-4ac}$

(a) $x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D$

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

D=0 means there is one real root with multiplicity 2

7 0

3 years ago

What numbers does the square root of 125 fall between

attashe74 [19]

9 and 10

11 and 12

13 and 14

15 and 16

the square root of 125 is 11.18 so therefore it falls between 11 and 12

3 0

3 years ago

Read 2 more answers

What is half of 31 over 50

____ [38]

31 divided by 50 is 0.62

4 0

3 years ago

Read 2 more answers

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

3 years ago