Answer:
Tan C = 3/4
Step-by-step explanation:
Given-
∠ A = 90°, sin C = 3 / 5
<u>METHOD - I</u>
<u><em>Sin² C + Cos² C = 1</em></u>
Cos² C = 1 - Sin² C
Cos² C = 
Cos² C = 
Cos² C = 
Cos C = 
Cos C = 
As we know that
Tan C = 
<em>Tan C = 
</em>
<em>Tan C = 
</em>
<u>METHOD - II</u>
Given Sin C = 
therefore,
AB ( Height ) = 3; BC ( Hypotenuse) = 5
<em>∵ ΔABC is Right triangle.</em>
<em>∴ By Pythagorean Theorem-</em>
<em>AB² + AC² = BC²</em>
<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>
<em>AC² = 5² - 3²</em>
<em>AC² = 25 - 9</em>
<em>AC² = 16</em>
<em>AC ( Base) = 4</em>
<em>Since, </em>
<em>Tan C = 
</em>
<em>Tan C = 
</em>
<em>Hence Tan C = </em>
<em />
Answer:
c and D
Step-by-step explanation:
beacuse if it's only rotated nothing changes
Here is the work:
(13x - 5x) + 12 - 2y = 6
(8x) + 12 - 2y = 6
-2y = -8x - 12 + 6
-2y = -8x - 6
y = 4x + 3
This one above lol ,......................m
a) Number of seats expected to be empty = 18
b) Number of passengers expected to show up for the flight = 291
Step-by-step explanation:
Step 1:
Probability that a passenger will not show up for the flight = 6%
Total capacity of the flight when fully booked = 300
Step 2 :
a)
Number of seats expected to be empty = 6% of 300 = 
× 300 = 18
b)
Number of passengers over booked = 10
Probability that a passenger will turn up for a flight = 100 - 6% = 94%
Number of passengers when the flight is overbooked = 300 + 10 = 310
Hence number of passengers who are expected to show up for the flight = 94% of 310 = 
× 310 = 291.4 = 291 (rounded of whole number as this represents number of passengers)
Step 3 :
Answer :
a) Number of seats expected to be empty = 18
b) Number of passengers expected to show up for flight = 291
