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Anon25 [30]
3 years ago
5

What is 9 wholes and 8:3 in simplest form

Mathematics
1 answer:
Mila [183]3 years ago
3 0
It is 9 and 8:3.It is because 8 and 3 do not have any factors that are the same especially because 3 is a prime number.A prime number is a number that has only a factor of itself and 1
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Help, please!! What is mA?
Inga [223]

Answer:

38°

Step-by-step explanation:

The measure of required angle can be obtained by using cosine law.

From the given triangle we find that:

a = 5, b = 3, c = 7,

Since,

cos (A) = (b^2 +c^2 - a^2) /2bc

Therefore,

cos (A) = (3^2 + 7^2 - 5^2) /(2*3*7)

cos (A) = (9 + 49 - 25) /(42)

cos (A) = (33) /(42)

cos (A) = 0.785714286

A = arccos(0.785714286)

A = 38.213210675°

A = 38°

4 0
4 years ago
Ms. Romero asks the student to genefractionrate an equivalent fraction. for 6/10.Gwen says 3/5 is an equivalent fraction while d
Phoenix [80]
Gwen is right 3\5 is equivalent to 6\10
if you divide 6\10 by 2 you will get 3\5
7 0
3 years ago
Simplify by dividing negative three over eight divided by five over nine..
IRISSAK [1]

Answer:

-15/24 or -0.625

Step-by-step explanation:

-3/8 ÷ 5/9

First, we can use the multiplication fraction conversion trick to switch the last fraction's numerator and denominator

It would look like this: -3/8 x 9/5

Use the cross out method to simplify the fractions as lowest as possible

-1/8 x 3/5 = -15/24

6 0
4 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
if the unit price for oranges is $0.26 per pound and Jim pays $2.08 for oranges, how many puns of oranges does he buy? A) 4.5 po
Nata [24]
Hey there!

If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:

0.26o = 2.08

We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.

To isolate o, we divide both sides by .26 to get:

The answer is C- Jim bought 8 oranges.

Hope this helps!
4 0
3 years ago
Read 2 more answers
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