To solve the problem it is necessary to apply the conservation equations of the moment.
The conservation equation of the moment is defined as,
Where,
Mass of Bird
Mass of Insect
Velocity Bird before swallowing
Velocity of insect
final velocity (both)
Replacing with our values we have,
Therefore the bird's speed immediately after swallowing is 7.83m/s
Answer:Paper and plastic!
Explanation:
Answer:
0.356 times the mass pass through equilibrium per second.
Explanation:
Given that,
Spring constant = 10 N/m
Mass = 2 kg
Stretched spring = 2m
We need to calculate the frequency
Using formula of frequency
Where, m = mass
k = spring constant
Put the value into the formula
We know that,
Hertz = cycle per second
Hence, 0.356 times the mass pass through equilibrium per second.
Answer:
2kg
Explanation:
∆p=mv m=∆p/v. (3.0kg*m/s)/1.5m/s