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4 years ago

13

Does an object in rest have potential energy

1 answer:

kenny6666 [7]4 years ago

4 0

Yes, of course! by it's definition the potential energy is an energy that particle have in order to obtain kinetic energy. Or simply an energy to make some movement.

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An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp

il63 [147K]

Answer:

$E_0 = 2180.53N/C.$

$B_0 = 7.27*10^{-6}T.$

$U_{avg} = 4.2*10^{-5}J/m^3.$

Explanation:

The Intensity $I$ of the beam is

$I = P /A$

The diameter of the beam is 0.900mm; therefore, the area is

$A = \pi( \dfrac{0.900*10^{-3}}{2} )^2$

$A = 6.36*10^{-7}m^2$

and since $P = 4.00*10^{-3}W$ , the intensity of the beam is

$I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}$

$\boxed{I = 6289.3W/m^2.}$

Now, the intensity $I$ is related to $E_0$ by the relation

$I = \dfrac{E_0^2}{2\mu_0 c}$

solving for $E_0$ we get

$E_0 = \sqrt{2\mu_0 c I}$

putting in the numbers we get:

$E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}$

$\boxed{E_0 = 2180.53N/C.}$

The amplitude of magnetic field $B_0$ is related to $E_0$ by

$B_0 = \dfrac{E_0}{c}$

putting in numerical values we get:

$B_0 = \dfrac{2180.53}{3*10^8}$

$\boxed{B_0 = 7.27*10^{-6}T. }$

The average energy density of the laser light is

$U_{avg} = \epsilon_0 E_0^2$

$U_{avg} = (8.85*10^{-12}) (2180.53)^2$

$\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}$

8 0

4 years ago

What is the similarity between relative dating and radioactive dating?

tankabanditka [31]

They both provide a range of years of an object. I think. They’re just 2 different ways to tell the age of fossils or rocks

4 0

3 years ago

angie is moving a couch with a mass of 48 kg. she moves it in 120 seconds using 240 j of work. what is her power output

natta225 [31]

Power =(work done) / (time to do the work) = 240 J / 120 sec = 2 watts.

8 0

3 years ago

A water pipe having a 4.00 cm inside diameter carries water into the basement of a house at a speed of 1.00 m/s and a pressure o

posledela

Answer:

$8.16\ \text{m/s}$

Explanation:

$d_1$ = Initial diameter = 4 cm

$v_1$ = Initial velocity = 1 m/s

$d_2$ = Final diameter = 7.8 m

$v_2$ = Final velocity

$A$ = Area = $\pi\dfrac{d^2}{4}$

From the continuity equation we get

$A_1v_1=A_2v_2\\\Rightarrow \pi\dfrac{d_1^2}{4}v_1=\pi\dfrac{d_2^2}{4}v_2\\\Rightarrow v_2=\dfrac{d_1^2}{d_2^2}v_1\\\Rightarrow v_2=\dfrac{4^2}{1.4^2}\times 1\\\Rightarrow v_2=8.16\ \text{m/s}$

The speed of water at the second floor is $8.16\ \text{m/s}$ .

8 0

3 years ago

A ball with a mass of 500g is lifted to a shelf 2 meter above ground. Calculate for the gravitational potential energy gained by

wariber [46]

Givens

500 grams = 500 grams * [1 kg/1000 grams] = 0.5 kg
h = 2 meters
g = 9.81

Formula

PE = m*g*h

Solution

PE = 0.5 * 9.81 * 2

PE = 9.81 Joules

7 0

3 years ago