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lubasha [3.4K]
3 years ago
15

A health clinic uses a solution of bleach to sterilize petri dishes in which cultures are grown. the sterilization tank contains

90 gal of a solution of 4% ordinary household bleach mixed with pure distilled water. new research indicates that the concentration of bleach should be 8% for complete sterilization. how much of the solution should be drained and replaced with bleach to increase the bleach content to the recommended level?
Chemistry
1 answer:
Dahasolnce [82]3 years ago
8 0
<span>3.75 gallons need to be drained and replaced with bleach. Change the problem to "What amounts of a 100% solution and a 4% solution is needed to make 90 gallons of a 8% solution?" Given that, we'll use the following values. x = amount of 4% solution. 90-x = amount of a 100% solution. The equation to solve then becomes. 0.04 x + (90-x) = 0.08 * 90 0.04 x + 90 - x = 7.2 Add x to both sides 0.04x + 90 = 7.2 + x Subtract 0.04x from both sides 90 = 7.2 + 0.96x Subtract 7.2 from both sides 82.8 = 0.96x Divide both sides by 0.96 86.25 = x So you now know that you need 86.25 gallons of the original 4% solution and (90-86.25) = 3.75 gallons of the bleach to make the desired 90 gallons. So simply drain 3.75 gallons from the tank and replace with bleach.</span>
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damaskus [11]

Answer:

1)This type of reaction is called thermal decomposition . Copper carbonate is green and copper oxide is black. You can see a colour change from green to black during the reaction. The carbon dioxide produced can be detected using limewater, which turns milky. 2) The extremely low pressure of the partial vacuum inside the can made it possible for the pressure of the air outside the can to crush it. A can is crushed when the pressure outside is greater than the pressure inside, and the pressure difference is greater than the can is able to withstand.

Explanation:

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7 0
3 years ago
3. A compound was analyzed and found to contain 9.8 g of nitrogen, 0.70 g of
Nesterboy [21]

Answer:

HNO₃

Explanation:

Data given

Nitrogen = 9.8 g

Hydrogen =  0.70 g

Oxygen = 33.6 g

Empirical formula = ?

Solution:

Convert the masses to moles

For Nitrogen

Molar mass of N = 14 g/mol

                              no. of mole = mass in g / molar mass

Put value in above formula

                          no. of mole = 9.8 g/ 14 g/mol

                          no. of mole = 0.7

                           mole of N = 0.7 mol

For Hydrogen

Molar mass of H = 1 g/mol

                     no. of mole = mass in g / molar mass

Put value in above formula

                     no. of mole = 0.70 g/ 1 g/mol

                      no. of mole = 0.7

mole of H = 0.7 mol

For Oxygen

Molar mass of O = 16 g/mol

                       no. of mole = mass in g / molar mass

Put value in above formula

                       no. of mole = 33.6 g / 16 g/mol

                       no. of mole = 2.1

mole of O = 2.1 mol

Now we have values in moles as below

N = 0.7

H = 0.7

O = 2.1

Divide the all values on the smallest values to get whole number ratio

N = 0.7 / 0.7 = 1

H = 0.7 / 0.7 = 1

O = 2.1 / 0.7 = 3

So all have following values

N = 1

H = 1

O = 3

So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.

6 0
3 years ago
When baking soda is added to a solution of citric acid, the temperature of the
Eduardwww [97]

I believe it's (C) Endothermic reaction

Explanation:

When energy is absorbed in an endothermic reaction, the temperature decreases.

3 0
3 years ago
Read 2 more answers
Calculate the molarity of a sodium hydroxide solution if 50.0 mL of this solution was completely neutralized by 46.6 mL of 0.750
Elodia [21]

Answer: 0.699 M

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(0.750)(46.6)=M_{B}(50.0)\\M_{B}=\frac{0.750)(46.6)}{50.0}=\boxed{0.699 \text{ M}}

3 0
1 year ago
A helium laser emits light with a wavelength of 633 nm. What is the frequency, v, of the light?​
Elanso [62]

Answer:

4.74×10¹⁴ Hz.

Explanation:

From the question given above, the following data were obtained:

Wavelength of light = 633 nm.

Frequency of light =?

Next, we shall convert 633 nm to metre (m)

This can be obtained as follow:

1×10⁹ nm = 1 m

Therefore,

633 nm = 633 nm × 1 m / 1×10⁹ nm

633 nm = 6.33×10¯⁷ m

Thus, 633 nm is equivalent to 6.33×10¯⁷ m

Finally, we shall determine the frequency of the light as follow:

Wavelength of light = 6.33×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency of light =?

Velocity = wavelength x frequency

3×10⁸ = 6.33×10¯⁷ x frequency

Divide both side by 6.33×10¯⁷

Frequency = 3×10⁸ / 6.33×10¯⁷

Frequency = 4.74×10¹⁴ Hz.

Therefore, the frequency of the light is 4.74×10¹⁴ Hz.

8 0
2 years ago
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