Answer:
1)This type of reaction is called thermal decomposition . Copper carbonate is green and copper oxide is black. You can see a colour change from green to black during the reaction. The carbon dioxide produced can be detected using limewater, which turns milky. 2) The extremely low pressure of the partial vacuum inside the can made it possible for the pressure of the air outside the can to crush it. A can is crushed when the pressure outside is greater than the pressure inside, and the pressure difference is greater than the can is able to withstand.
Explanation:
hope this helps you :)
Answer:
HNO₃
Explanation:
Data given
Nitrogen = 9.8 g
Hydrogen = 0.70 g
Oxygen = 33.6 g
Empirical formula = ?
Solution:
Convert the masses to moles
For Nitrogen
Molar mass of N = 14 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 9.8 g/ 14 g/mol
no. of mole = 0.7
mole of N = 0.7 mol
For Hydrogen
Molar mass of H = 1 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 0.70 g/ 1 g/mol
no. of mole = 0.7
mole of H = 0.7 mol
For Oxygen
Molar mass of O = 16 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 33.6 g / 16 g/mol
no. of mole = 2.1
mole of O = 2.1 mol
Now we have values in moles as below
N = 0.7
H = 0.7
O = 2.1
Divide the all values on the smallest values to get whole number ratio
N = 0.7 / 0.7 = 1
H = 0.7 / 0.7 = 1
O = 2.1 / 0.7 = 3
So all have following values
N = 1
H = 1
O = 3
So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.
I believe it's (C) Endothermic reaction
Explanation:
When energy is absorbed in an endothermic reaction, the temperature decreases.
Answer:
4.74×10¹⁴ Hz.
Explanation:
From the question given above, the following data were obtained:
Wavelength of light = 633 nm.
Frequency of light =?
Next, we shall convert 633 nm to metre (m)
This can be obtained as follow:
1×10⁹ nm = 1 m
Therefore,
633 nm = 633 nm × 1 m / 1×10⁹ nm
633 nm = 6.33×10¯⁷ m
Thus, 633 nm is equivalent to 6.33×10¯⁷ m
Finally, we shall determine the frequency of the light as follow:
Wavelength of light = 6.33×10¯⁷ m
Velocity of light = 3×10⁸ m/s
Frequency of light =?
Velocity = wavelength x frequency
3×10⁸ = 6.33×10¯⁷ x frequency
Divide both side by 6.33×10¯⁷
Frequency = 3×10⁸ / 6.33×10¯⁷
Frequency = 4.74×10¹⁴ Hz.
Therefore, the frequency of the light is 4.74×10¹⁴ Hz.