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Korolek [52]
3 years ago
8

Compare and contrast the uses of the iron triad and the use of the coinage metals

Chemistry
1 answer:
stira [4]3 years ago
7 0
<span>he iron triad has the most variable oxidation states from +6, etc. The coinage metals have oxidation states of +1 except for copper which can also be +2. The zinc group have common oxidation states of +2 except for mercury which can also have +1. The coinage and zinc groups cannot have oxidation states greater than 2 under normal conditions.</span>
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g Nitrogen in the atmosphere consists of two nitrogen atoms covalently bonded together (N2). Knowing that nitrogen is atomic num
vichka [17]

Explanation:

Since, the atomic number of nitrogen is 7 and its electronic distribution is 2, 5. So, in order to attain stability it needs to gain 3 electrons.

Hence, when it chemically combines another nitrogen atom then as both the atoms are non-metals. So, sharing of electrons will take place.

Also, there is no difference in electronegativity of two nitrogen atoms. Hence, compound formed N_{2} is non-polar covalent in nature.

5 0
3 years ago
If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assum
Marta_Voda [28]

Answer:

B.) 1.3 atm

Explanation:

To find the new pressure, you need to use Gay-Lussac's Law:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.

P₁ = 1.2 atm                                    P₂ = ? atm

T₁ = 20 °C + 273 = 293 K              T₂ = 35 °C + 273 = 308 K

P₁ / T₁ = P₂ / T₂                                             <----- Gay-Lussac's Law

(1.2 atm) / (293 K) = P₂ / (308 K)                  <----- Insert values

0.0041 = P₂ / (308 K)                                   <----- Simplify left side

1.3 = P₂                                                         <----- Multiply both sides by 308

3 0
1 year ago
This characteristic of hydrogen and oxygen make the water molecule polar: ______.
Finger [1]

Answer:

thé answer is b ) electronegativity

5 0
3 years ago
The molar mass of HgO is 216.59 g/mol. The molar mass of O2 is 32.00 g/mol. How many moles of HgO are needed to produce 250.0 g
Irina-Kira [14]
A reaction in which Oxygen (O₂) is produced from Mercury Oxide (HgO) would be a decomposition reaction.
           2HgO    →    2Hg    +    O₂

If 250g of O₂ is needed to be produced,
then the moles of oxygen needed to be produced = 250g  ÷  32 g/mol
                                                                                     = 7.8125 mol

Now, the mole ratio of Oxygen to Mercury Oxide is  1  :  2
∴ if the moles of oxygen =  7.8125 mol
then the moles of mercury oxide = 7.8125 mol × 2
                                                        = 15.625 mol


Thus the number moles of HgO needed to produce 250.0 g of O₂ is 15.625 mol
 
6 0
3 years ago
After completion of the citric acid cycle, most of the usable energy from the original glucose molecule is in the form of ______
GaryK [48]

After completion of the citric acid cycle, most of the usable energy from the original glucose molecule is in the form of B. ATP

The most basic kind of sugar, monosaccharides only have one kind of sugar molecule. The simplest sugar is glucose, which is also your body's primary energy source. In tests to determine blood sugar levels, sugar is measured. Fructose and galactose, two more monosaccharides, are converted into glucose via metabolism ( 1 , 2 ). For instance, ATP is necessary for both breathing and keeping your heart beating. As well as assisting in the synthesis of lipids and nerve impulses, ATP also facilitates the entry and exit of certain molecules from cells. Even some living things, including bioluminescent creatures like jellyfish and fireflies, use ATP to create light!

Learn more abut ATP here:

brainly.com/question/14637256

#SPJ4

5 0
1 year ago
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