All categories

3 years ago

Compare and contrast the uses of the iron triad and the use of the coinage metals

1 answer:

7 0

he iron triad has the most variable oxidation states from +6, etc. The coinage metals have oxidation states of +1 except for copper which can also be +2. The zinc group have common oxidation states of +2 except for mercury which can also have +1. The coinage and zinc groups cannot have oxidation states greater than 2 under normal conditions.

You might be interested in

Which of the following sentences best describes what is shown in the above picture?

velikii [3]

Answer:

Cells of a multicellular organism

5 0

3 years ago

Read 2 more answers

NO LINKS PLEASE! Why does dye dropped into a cup of water eventually spread throughout the water?

Nezavi [6.7K]

Answer:

Explanation:

okay, you need to look at the structures of the particles of matter in the solid, liquid and gas.

particles in a solid are in fixed positions, where they can only vibrate in those positions ( take a look at ice, or rather, a brick)
liquids have very small or rather, no spaces between them, but they can slide or rub against each other, like people in a really tight crowd I guess
gas particles have very large spaces between them and they move randomly. these exibit what's called brownian motion.

since water particles (and all other liquid particles) have negligible spacings and limited movement, that allows the dye particles to move from a region of high concentration to that of a low concentration. the aim for this is for the mixture/solution to reach an equilibrium, that is the mixture must get to a point where all regions have the same concentration of the dye.

you can refer to your coursebooks :)

correct where wrong please:)

5 0

2 years ago

Calculate the amount in moles of 125 g of CaSO4.

Leto [7]

Answer:

Number of moles = 0.92 mol

Explanation:

Given data:

Mass of CaSO₄ = 125 g

Number of moles of CaSO₄ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CaSO₄:

Molar mass of CaSO₄ = 40 + 32+ 16×4

Molar mass of CaSO₄ = 40 + 32+ 64

Molar mass of CaSO₄ = 136 g/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 125 g/ 136 g/mol

Number of moles = 0.92 mol

7 0

3 years ago

What is the lower concentration limit (vol%) at which a mixture of ethanol in air can explode?

liubo4ka [24]

Answer:

Lower explosive limit (LEL) of ethanol = 3.3%

Explanation:

In the case of alcohol, ethanol presents certain fire hazards. Its momentary flash point is 55ºF (12.9ºC), while the momentary flash point of gasoline is -45ºF (-42.8ºC), and the E85 mixture ranges between -20ºF and -4ºF (between -28 , 9ºC and -20ºC), and has a wider range of flammability limits than gasoline. For emergency response teams, this implies that during a release of the typical ethanol / gasoline mixture, the fuel can be expected to behave like gasoline: It is heavier than air - as we mentioned earlier - and can produce vapors and form flammable mixtures in the air, under most environmental conditions.

General properties and comparison with other inflambles products:

Flash point momentary Gasoline = -45 ° F

Ethanol = 55 ° F

E 85 = between -20º and -4º F

Flammability limits

Lower explosive limit (LEL) of ethanol = 3.3%

Upper Explosive Limit (UEL) = 19%

Lower explosive limit (LEL) of the mixture E 85 = 1.4%

Upper Explosive Limit (UEL) 85 = 19%

Lower explosive limit (LEL) of gasoline = 1.4%

Upper Explosive Limit (UEL) = 7.6%

They have a wider range than gasoline

4 0

3 years ago

Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.

o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

vHe / vNe = 2.24

I hope it helps!

8 0

3 years ago