<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the concentration of unknown phosphoric acid solution is 0.034 M
(a) 3.33 mol Bi
Explanation:
Step 1: Convert 283 g to moles
Bi Molar Mass - 208.98 g/mol × 2 = 417.98 g/mol
O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol
283 g Bi₂O₃ ÷ 465.98 g/mol = 0.0607 mol Bi₂O₃
Step 2: Find the conversion from Bi₂O₃ to Bi
1 mole of Bi₂O₃ equals 2 moles of Bi
Step 3: Use Dimensional Analysis
1.66316 mol · = 3.32632 mol Bi
3.32632 mol Bi ≈ 3.33 mol Bi
What is bismuth oxide used for?
Bismuth oxides have been considered as an interesting material because of their dielectric properties and have been used for applications such as optical coatings, metal-insulator-semiconductor capacitors and microwave-integrated circuits.
What is bismuth used for in everyday life?
Bismuth finds its main uses in pharmaceuticals, atomic fire alarms and sprinkler systems, solders and other alloys and pigments for cosmetics, glass and ceramics. It is also used as a catalyst in rubber production
Learn more about bismuth oxide:
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Answer:
The answer will be A
Explanation:
A scientific law is based on repeated experiments or observations, that describe or predict a range of natural phenomena. A scientific law is something that is unexpected
Answer:
Explanation:
Data Given
Formula of hydrazine = N₂H₄
Lewis structure of hydrazine (N₂H₄) =?
Solution:
- Hydrazine (N₂H₄) contains 2 Nitrogen atoms and 4 Hydrogen atoms
- Nitrogen atom have 5 valence electrons
- Hydrogen have 1 valance electron
- So it have 14 total number of valance electrons
N₂ H₄ = 2 (5) + 4(1) = 14 no. o electrons
- it is a stable compound and obey octet rule for nitrogen and duplet rule for hydrogen by sharing of electrons.
To draw the Lewis Structure
- Put the 2 nitrogen in center and draw the Hydrogen on the outside
- Put the 2 hydrogen on out side of each of the nitrogen
- Then draw the 2, 2 valence electrons between atoms that form chemical bond
- So we will draw total 14 electrons in the structure
- then we count electrons around each atom of nitrogen and hydrogen that it have 8 and 2 electrons to complete its octet and duplet respectively
Lewis Structure of N₂ H₄ in attachment