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Lubov Fominskaja [6]
4 years ago
13

Give the quantum number set for one electron in the 3p sub level of a sulfur (S)

Chemistry
1 answer:
vesna_86 [32]4 years ago
3 0

Answer:- Atomic number for sulfur is 16 and it's electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^4. Here, there are total for electrons in 3p and the set of quantum numbers for these 4 electrons would be as..

For the first electron of 3p-

n = 3, l = 1, ml = -1 and ms = +(1/2)

for the second electron of 3p-

n = 3, l = 1, ml = 0 and ms = +(1/2)

for the third electron of 3p-

n = 3, l = 1, ml = +1 and ms = +(1/2)

and for the fourth electron of 3p-

n = 3, l = 1, ml = -1 and ms = -(1/2)

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Option (B) is the right answer.

Hydronium ion (H_{3}O^{+}) concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.

<h3>What is pH?</h3>

The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) : pH = -log_{10}[H_{3}O^{+}  ]

Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.

<h3>Given: </h3>

pH1( initial pH) = 2.0

pH2( initial pH) = 4.0

[H3O+] =  initial hydronium concentration

[H3O+]* = final hydronium concentration

<h3>Formula used : </h3>

pH = -log_{10}[H_{3}O^{+}]

<h3>Solution: </h3>

pH = - log_{10}[H_{3}O^{+}] \\\\= > 10^{-pH} = [H_{3}O^{+}] \\\\similarly, \\\\10^{-pH} = [H_{3}O^{+}]*\\\\ = > 10^{-4} = [H_{3}O^{+}]*\\\\Now, \frac{[H_{3}O^{+}]*}{[H_{3}O^{+}]}  = 10^{-2}

Thus , the concentration of hydronium ion decreases by 100.

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