Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
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Answer:
d.It must show the reactants and products on the correct sides of
the reaction arrow
Explanation:
hope it helps
Answer:
Answer below
Explanation:
Just draw a photo of someone pushing an object across a table. Your push is the force acting on the object you're pushing.
Answer: Membrane Protiens
Explanation:
In facilitated diffusion, molecules diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers. A concentration gradient exists for these molecules, so they have the potential to diffuse into (or out of) the cell by moving down it.
Option (B) is the right answer.
Hydronium ion (
) concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.
<h3>What is pH?</h3>
The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) : ![pH = -log_{10}[H_{3}O^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-log_%7B10%7D%5BH_%7B3%7DO%5E%7B%2B%7D%20%20%5D)
Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.
<h3>Given: </h3>
pH1( initial pH) = 2.0
pH2( initial pH) = 4.0
[H3O+] = initial hydronium concentration
[H3O+]* = final hydronium concentration
<h3>Formula used : </h3>
![pH = -log_{10}[H_{3}O^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-log_%7B10%7D%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
<h3>Solution: </h3>
![pH = - log_{10}[H_{3}O^{+}] \\\\= > 10^{-pH} = [H_{3}O^{+}] \\\\similarly, \\\\10^{-pH} = [H_{3}O^{+}]*\\\\ = > 10^{-4} = [H_{3}O^{+}]*\\\\Now, \frac{[H_{3}O^{+}]*}{[H_{3}O^{+}]} = 10^{-2}](https://tex.z-dn.net/?f=pH%20%3D%20-%20log_%7B10%7D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%5C%5C%5C%5C%3D%20%3E%2010%5E%7B-pH%7D%20%3D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%5C%5C%5C%5Csimilarly%2C%20%5C%5C%5C%5C10%5E%7B-pH%7D%20%3D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%2A%5C%5C%5C%5C%20%3D%20%3E%2010%5E%7B-4%7D%20%3D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%2A%5C%5C%5C%5CNow%2C%20%5Cfrac%7B%5BH_%7B3%7DO%5E%7B%2B%7D%5D%2A%7D%7B%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%20%20%3D%2010%5E%7B-2%7D)
Thus , the concentration of hydronium ion decreases by 100.
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