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3 years ago

Why do cats purr to get attention

1 answer:

5 0

Cats purr when they are stressed, in pain or sick because cat purrs have healing powers. Not all cat purrs are purrs of contentment. Cats purr when they are stressed, in pain or severely ill. ... There are also reports that cats heal faster than other animals that do not purr, and that purring releases endorphins.

hope this helped :)
alisa202

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Starting with 0.250L of a buffer solution containing 0.250 M benzoic acid (C 6H 5COOH) and 0.20 M sodium benzoate (C 6H 5COONa),

Zigmanuir [339]

Answer:

pH = 4.05

Explanation:

The pH of the benzoic buffer can be determined using H-H equation:

pH = pKa + log [A⁻] / [HA]

Where pKa is -logKa = 4.187

pH = 4.187 + log [Sodium Benzoate] / [Benzoic Acid]

Where [] can be understood as moles of each specie.

Thus, to find pH of the buffer we need to calculate moles of benzoic acid and sodium benzoate.

Initial moles:

Initial moles of benzoic acid and sodium benzoate are:

Acid: 250mL = 0.250L ₓ (0.250 moles / L) = 0.0625 moles of benzoic acid

Benzoate : 250mL = 0.20L ₓ (0.250 moles / L) = 0.050 moles of sodium benzoate

Moles after reaction:

Now, 0.0250L×(0.100mol/L) = 0.0025 moles of HCl are added to the buffer reacting with sodium benzoate, C₆H₅COONa, producing more benzoic acid, as follows:

HCl + C₆H₅COONa → C₆H₅COOH + NaCl

That means after reaction moles of both species are:

Benzoic acid: 0.0625 mol + 0.0025mol (Moles produced) = 0.065 moles

Sodium Benzoate: 0.050mol - 0.0025mol (Moles that react) = 0.0475 moles

Replacing in H-H equation:

pH = 4.187 + log [0.0475] / [0.065]

pH = 4.05

5 0

3 years ago

50.0kg of nitrogen and 10.0kg 0f hydrogen are mixed to produce ammonia . calculate the ammonia formed, identify the limiting rea

Nana76 [90]

Answer:

Nitrogen is limiting reactant and 30.4kg of ammonia can be formed

Explanation:

Nitrogen, N₂, reacts with hydrogen, H₂ to produce ammonia, NH₃, as follows:

2N₂ + 3H₂ → 2NH₃

Where 2 moles nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles and the mass of ammonia formed as follows:

Moles N2 -Molar mass: 28g/mol-

50000g * (1mol / 28g) = 1786 moles N2

Moles H2 -Molar mass: 2g/mol-

10000g * (1mol / 2g) = 5000 moles H2

For a complete reaction of 5000 moles H2 are needed:

5000 mol H2 * (2mol N2 / 3mol H2) = 3333 moles N2. As there are just 1786 moles, Nitrogen is limiting reactant

The moles of ammonia that can be produced are 1786 moles because 2mol N2 = 2moles NH3.

The mass of ammonia -Molar mass NH3: 17g/mol- is:

1786 moles NH3 * (17g / mol) = 30362g =

30.4kg of ammonia can be formed

3 0

3 years ago

Consider the chemical reaction in equilibrium.

icang [17]

The correct option is A.
The chemical equation given above is an endothermic reaction. An endothermic reaction is a type of reaction which absorb heat from the environment. An endothermic reaction needs heat to occur, therefore, increasing the temperature of such a reaction will favor the formation of more product and the equilibrium of the reaction will shift [forward] to the right, which is the product side.

6 0

3 years ago

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djverab [1.8K]

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3 years ago

The picture (below) shows the formula for ___________.

Stella [2.4K]

Answer:

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