Answer:
16.53 pounds
Explanation:
this type of problem needs convertion method we need to convert from grams to pound.
it is over 32 degrees Fahrenheit (freezing), and below 120 degrees Fahrenheit (boiling)
Answer:
22.77 g.
he limiting reactant is O₂, and the excess reactant is Mg.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:
no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.
no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.
So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.
<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>
Answer:
0.4033 M is the concentration of the sodium hydroxide solution.
Explanation:
Mass of potassium hydrogen phthalate = 2.023 g
Molar mass of potassium hydrogen phthalate = 204.22 g/mol
Moles of potassium hydrogen phthalate :
= 
According to reaction, 1 mole of potassium hydrogen phthalate reacts with 1mole of NaOH. Then 0.009906 moles of potassium hydrogen phthalate will recat with:
of NaOH
Moles of NaOH = 0.009906 mol
Volume of NaOH solution = 24.56 mL = 0.02456 L
![[NaOH]=\frac{0.009906 mol}{0.02456 L}=0.4033 M](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5Cfrac%7B0.009906%20mol%7D%7B0.02456%20L%7D%3D0.4033%20M)
0.4033 M is the concentration of the sodium hydroxide solution.
They contain different amounts of protons within them.
