What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?

2 answers:

4 0

The structural formula of 2-methylbutan-2-ol is in Word document below.
2-methyl-2-butanol is organic compound and belongs to alcohols. Hydroxyl functional group is on second saturated carbon atom of butane and also methyl group (-CH₃) is on second saturated carbon atom of main chain (butane).

Download docx

olganol [36]3 years ago

4 0

Answer:

 CH3
 |
CH3 - C - CH2 - CH3
 |
 OH

Explanation:

1) given name: 2-methylbutan-2-ol

2) that means:

- the main chain is a butane (4 carbon atoms): CH3 - CH2 - CH2 - CH3

- 2 methyl => there is a methyl group in the second carbon =>

 CH3
 |
CH3 - CH - CH2 - CH3

- 2 - ol => there is a hydroxil (OH) group in the second carbon =>

 CH3
 |
CH3 - C - CH2 - CH3
 |
 OH

And that is the structure of the compound.

You might be interested in

A television weights 8.50 pounds. How many grams is this?

kolezko [41]

Answer:

3,855.532 grams

Explanation:

1 pound = 453.592 grams

8.50 = ? grams

--> 8.50 * 453.592 = 3,855.532 grams.

4 0

3 years ago

Which type of bond is found between atoms of solid cobalt?

Vsevolod [243]

The answer is (3) metallic. Cobalt is a transition metal, so it can't be covalent bonds, which bond non-metals, therefore eliminating choice 1 and 2. Ionic bonds are between metals and non metals, but solid cobalt does not have a non metal, eliminating choice 4 as well. Metallic bonds are bonds between metals, therefore the answer is (3) metallic.

3 0

3 years ago

Read 2 more answers

Which elements form are ionic compounds check all the boxes that apply

morpeh [17]

Answer/Explanation:

Aluminum and oxygen

Fluorine and oxygen

Ionic compounds are formed when any type of metal is combined with a non-metal such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium.

(any)metal + nonmetal = ionic compound

7 0

3 years ago

48g of 02 produce how many grams of Al2O3

bixtya [17]

Taking into account the reaction stoichiometry, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Al + 3 O₂ → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 4 moles
O₂: 3 moles
Al₂O₃: 2 moles

The molar mass of the compounds is:

Al: 27 g/mole
O₂: 32 g/mole
Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 4 moles ×27 g/mole= 108 grams
O₂: 3 moles ×32 g/mole= 96 grams
Al₂O₃: 2 moles ×102 g/mole= 204 grams

<h3>Mass of Al₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

$mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}$