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Gnom [1K]
3 years ago
11

What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?

Chemistry
2 answers:
grigory [225]3 years ago
4 0
<span>The structural formula of 2-methylbutan-2-ol is in Word document below.
</span>2-methyl-2-butanol is organic compound and belongs to alcohols. Hydroxyl <span>functional group is on second saturated carbon atom of butane and also methyl group (-CH</span>₃) is on second saturated carbon atom of main chain (butane).<span>

</span>
Download docx
olganol [36]3 years ago
4 0
Answer:

<span><span>            CH3
             |
  CH3 - C - CH2 - CH3</span>
             |
            OH</span>


Explanation:

1) given name: <span>2-methylbutan-2-ol

2) that means:

- the main chain is a butane (4 carbon atoms): CH3 - CH2 - CH2 - CH3

- 2 methyl => there is a methyl group in the second carbon =>

            CH3
             |
  CH3 - CH - CH2 - CH3

- 2 - ol => there is a hydroxil (OH) group in the second carbon =>
</span>
<span><span>            CH3
             |
  CH3 - C - CH2 - CH3</span>
             |
            OH

And that is the structure of the compound.

</span>

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A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

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1) A common experiment to determine the relative reactivity of metallic elements is to place a pure sample of one metal into an
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Explanation:-

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As zinc is more reactive than copper, it could easily displace copper from its aqueous solution and thus leads to formation of zinc (II) sulfate and pure copper.

The chemical reaction can be represented as :

Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

The phases are represented as (s) for solid sate, (l) for liquid state, (g) for gaseous state and (aq) for aqueous state.

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Answer:

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