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Lyrx [107]
3 years ago
14

Draw a structural formula for 4,4-dichlorocyclohexanecarboxylic acid.

Chemistry
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

See attached picture.

Explanation:

Hello,

In this case, for the required carboxylic acid, we should consider a central cyclohexane that at the first carbon has a carboxyl group COOH and at the fourth carbon has two chlorine radicals as shown on the attached picture. This type of compounds need to have the carboxyl group outside the ring in order to be considered as acids, otherwise the octet rule may not be respected for a cyclic carbon.

Regards.

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Ann [662]
The answer is c because ice is cold
4 0
4 years ago
How many moles of ammonia gas occupy 50 mL at at 700 kPa and 30.0 0C?
nalin [4]

For the conversions

I will start with pressure
1atm=101.3kPa
x =700kPa
x=700kPa/101.3kPa
x=6.91atm

Temperature
273K+30.00C
303K

Volume
1L=1000ml
x =50ml
x=0.05L

PV=nRT
6.91*0.05=n*0.08206*303
0.3455=24.86418n
0.3455/24.86418=n
0.0138=n
number of moles = 0.0138moles

Note: 0.08206 is the gas constant in this case
6 0
3 years ago
What process transform solar energy into chemical energy?
DIA [1.3K]
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8 0
3 years ago
Relation between glancing and angle of deviation<br>​
shtirl [24]

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0
3 years ago
Consider the reaction of CaCN2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How m
adelina 88 [10]

Answer:

56 g. Option 3.

Explanation:

The reaction is: CaCN₂ + 3H₂O → CaCO₃ + 2 NH₃

1 mol of calcium cianide reacts with 3 moles of water in order to produce 1 mol of calcium carbonate and 2 moles of ammonia

We have the mass of each reactant, so let's convert the mass to moles:

45 g. 1mol / 80.08 g = 0.562 moles of cianide

45 g. 1mol / 18 g = 2.5 moles of water

The cianide is the limiting reactant:

3 moles of water need 1 mol of cianide to react

Then, 2.5 moles of water will need (2.5 . 1)/ 3 = 0.833 moles

As we have 0.562 moles of CN⁻ we don't have enough

We can work now, on the reaction:

Ratio is 1:1. Therefore 0.562 moles of cianide will produce 0.562 moles of carbonate

Let's convert the mass to moles to find the answer:

0.562 mol . 100.08 g / 1 mol = 56.2 g

8 0
3 years ago
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