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Vilka [71]
2 years ago
14

Help please ill do anything really!!!!!!!

Chemistry
1 answer:
Volgvan2 years ago
5 0

Answer:

The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.

Explanation:

Hope it helps.

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Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 3.31 × 10−13 at some temperature, compute
Artyom0805 [142]
Since Kw= [H⁺][OH⁻], and the concentration of both substances are the same, the equation is now Kw=[H⁺]²
So,
3.31x10⁻¹³ = [H⁺]²
Take the square root= 5.75x10⁻⁷
Then take the negative log to find the pH:
-log(5.75x10⁻⁷) = 6.25
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3 years ago
Why is the mass of the third subatomic particle ignored?
dmitriy555 [2]

Answer: The mass of electrons is mostly ignored because electrons are extremely small compared to neutrons and protons.

Explanation: A proton is about 1,836 times the size of an electron.

On the periodic table, the atomic number for each element can be found. This number is found by measuring the weight of 6.02 x 10^23 atoms of the element in grams. Electrons aren't ignored when finding exact math, but for the sake of simplification high school teachers will generally have you only count the number of protons and neutrons when calculating the mass of atoms.

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1 year ago
Which element has higher ionization energy? chlorine or carbon
PtichkaEL [24]

Answer:

chlorine has higher ionization than carbon

Explanation:

Chlorine is only one row below carbon, but it is three columns to the right in this case the IP of chlorine would be predicted to be greater than the IP of carbon.

3 0
3 years ago
How many more oxygen atoms are in Na2HPO4H(disodium phosphate) then in 2H3PO(Phosphoric Acid)?
Serggg [28]

Answer:

in disodium phosphate = 4 oxygen atoms

in phosphoric acid = 1 oxygen atom

3 0
2 years ago
Read 2 more answers
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
3 years ago
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