<h3>
Answer:</h3>
3.33 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
60.0 g H₂O (Water)
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Convert</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.32963 mol H₂O ≈ 3.33 mol H₂O
Potential energy
Explanation:because when your not moving at the highest point you have potential energy
Answer:

Explanation:
= Density of acetic acid = 
= Mass of acetic acid = 
= Volume
Density is given by

The volume of acetic acid is
.
Given data:
Mass of cofactor A in an average yeast cell = 96.15 pg
Now:
1 picogram (pg) = 1*
g
1 microgram (ug) = 1*
g
Therefore, 1 pg = 1*
ug
Mass of cofactor A in one yeast cell = 96.15 *
micro gram
Number of cells in the yeast colony = 105
Therefore, the total mass of cofactor A is given as:
Number of cells * mass of cofactor A per cell
= 105 cells * 96.15 *
micro grams/cell = 1.009 *
micro grams