Answer:
The equilibrium temperature of the coffee is 72.4 °C
Explanation:
Step 1: Data given
Mass of cream = 15.0 grams
Temperature of the cream = 10.0°C
Mass of the coffee = 150.0 grams
Temperature of the coffee = 78.6 °C
C = respective specific heat of the substances( same as water) = 4.184 J/g°C
Step 2: Calculate the equilibrium temperature
m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)
15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)
62.76T2 - 627.6 = -627.6T2 + 49329.36
690.36T2 = 49956.96
T2 = 72.4 °C
The equilibrium temperature of the coffee is 72.4 °C
C
Sana makatulong answer ko
Volume:
a x b x c
Therefore:
5.54 x 10.6 cm x 199 => 11,686.076 cm³
Answer herbert
Explanation:
cause he did not do any of the safety precautions and he was prob not listening to the teacher
Answer:
It would be the last one because the way earth is tilted the sun rays would be pointing at the Northern Hemisphere more than the Southern Hemisphere
