A point is reflected over the y-axis, but the x-coordinate does not change. What is the location of the point? (0, 3) (-1, 0) (1
, 1) (-1, -1)
2 answers:
Answer:
Step-by-step explanation:
When we apply a reflection in a point over an axis this is what happens, especially if we consider, a reflexion of those points over y-axis
A(0,-3) B(-1,0) C(1,1) D(-1,-1)
Since the reflection over y-axis equals to (-x,y) we are going to have a change. But the question says we're not going to have any change at all. Calculating to prove it:
(-x,y) Reflection across y-axis
A(0,-3) then A'(0,-3)
B(-1,0) then =B'(1,0)
C(1,1) then C'(-1,1)
D(-1,-1) then D'(1,-1)
Hence the point is A, whose A' did not change its x-coordinate across the y-axis after reflected.
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Answer:
(x -3)² +(y -5)² = 36
Step-by-step explanation:
The center is on the vertical line halfway between the given vertical lines, so is at x=3. It is also on the horizontal line through the point (-3, 5), so is at y=5. The center is 9-3=6 from either tangent line, so this is the radius.
For center (h, k) and radius r, the circle's equation is ...
(x -h)² +(y -k)² = r²
For (h, k) = (3, 5) and r=6, the equation is ...
(x -3)² +(y -5)² = 36 . . . . . . . . does not match any choice written here
(a) m =
calculate the slope (m) using the ' gradient formula '
m =
let (x₁, y₁) = (8, 9) and (x₂, y₂) = ( - 2, 4)
m = =
=
(b) y - 9 = (x - 8)
the equation of a line in ' point- slope form ' is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
choose any of the 2 given points for (a, b) → (8, 9)
y - 9 = (x - 8) → " point- slope form"
(c) y = x + 5
the equation of a line in ' slope-intercept form ' is
y = mc + c
where m is the slope and c the y-intercept
expand and simplify the point- slope equation
y - 9 = x - 4
y = x - 4 + 9
y = x + 5 → " slope- intercept form"